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...the potential energy that you build while going up the hill on the roller coaster could be let go as kinetic energy -- the energy of motion that takes you down the hill of the roller coaster.
Answer:
The acceleration of the wagon is 3 m/s².
To calculate the acceleration of the wagon, we use the formula below.
Formula:
F = ma............. Equation 1
Where:
F = horizontal Force
m = mass of the wagon
a = acceleration of the wagon.
make a the subject of the equation
a = F/m.............. Equation 2
From the question,
Given:
F = 30 N
m = 10 kg
Substitute these values into equation 2
a = 30/10
a = 3 m/s²
Hence, the acceleration of the wagon is 3 m/s².
Answer:
over harvesting, pollution, introduction of invasive species such as new predators and food competitors
Explanation:
The main cause of mass extinction is Humans cause extinction of a species through overharvesting. The second main cause is pollution ., introduction of invasive species such as new predators and food competitors, habitat destruction, overhunting and other influences. Another very important cause of mass extinction is the unsustainable human population growth.
The five mass extinction events are
Ordovician Mass Extinction
Devonian Mass Extinction
Permian Mass Extinction
Triassic -Jurassic Mass Extinction
and Cretaceous -Tertiary (or the K-T) Mass Extinction.
To solve this problem we will apply the energy conservation theorem for which the work applied on a body must be equivalent to the kinetic energy of this (or vice versa) therefore
![W = \Delta KE](https://tex.z-dn.net/?f=W%20%3D%20%5CDelta%20KE)
![\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28m%29%28v_f%29%5E2%20-%5Cfrac%7B1%7D%7B2%7D%20%28m%29%28v_i%29%5E2)
Here,
m = mass
= Velocity (Final and initial)
First case) When the particle goes from 10m/s to 20m/s
![\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28m%29%28v_f%29%5E2%20-%5Cfrac%7B1%7D%7B2%7D%20%28m%29%28v_i%29%5E2)
![\Delta W = \frac{1}{2} (m)(20)^2 -\frac{1}{2} (m)(10)^2](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28m%29%2820%29%5E2%20-%5Cfrac%7B1%7D%7B2%7D%20%28m%29%2810%29%5E2)
![W_1 = 150(m) J](https://tex.z-dn.net/?f=W_1%20%3D%20150%28m%29%20J)
Second case) When the particle goes from 20m/s to 30m/s
![\Delta W = \frac{1}{2} (m)(v_f)^2 -\frac{1}{2} (m)(v_i)^2](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28m%29%28v_f%29%5E2%20-%5Cfrac%7B1%7D%7B2%7D%20%28m%29%28v_i%29%5E2)
![\Delta W = \frac{1}{2} (m)(30)^2 -\frac{1}{2} (m)(20)^2](https://tex.z-dn.net/?f=%5CDelta%20W%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28m%29%2830%29%5E2%20-%5Cfrac%7B1%7D%7B2%7D%20%28m%29%2820%29%5E2)
![W_1 = 250(m) J](https://tex.z-dn.net/?f=W_1%20%3D%20250%28m%29%20J)
As the mass of the particle is the same, we conclude that more energy is required in the second case than in the first, therefore the correct answer is A.