By using Ohm's law, we can calculate the resistance of the wire. Ohm's law states that:
where V is the potential difference across the conductor, I is the current and R the resistance. Rearranging the equation, we get
Now we can use the following equation to calculate the length of the wire:
(1)
where
is the resistivity of the material
L is the length of the conductor
A is its cross-sectional area
In this problem, we have a wire of copper, with resistivity
. The radius of the wire is half the diameter:
And the cross-sectional area is
So now we can rearrange eq.(1) to calculate the length of the wire:
Incomplete question as we have not told which quantity to find.So the complete question is here
A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.Given this, how large a current does it carry?
Answer:
Explanation:
Magnetic field B=1.5 T
Length L=2.2mm =0.0022m
Number of turns N=1300 turns
To find
Current I
Solution
From the magnetic at the center of loop we know that:
Substitute the given values
Answer:
No, the magnitude of the magnetic field won't change.
Explanation:
The magnetic field produced by a wire with a constant current is circular and its flow is given by the right-hand rule. Since this field is circular with center on the wire the magnitude of the magnetic field around the wire will be given by B = [(\mi_0)*I]/(2\pi*r) where (\mi_0) is a constant, I is the current that goes through the conductor and r is the distance from the wire. If the field sensor will move around the wire with a fixed radius the distance from the wire won't change so the magnitude of the field won't change.
Explanation:
Its translational kinetic energy is:
KE = ½ mv²
It's rotational kinetic energy is:
RE = ½ Iω²
For a solid sphere, I = ⅖ mr², and since it's not slipping, ω = v/r.
RE = ½ (⅖ mr²) (v/r)²
RE = ⅕ mv²
Therefore, the translational kinetic energy is larger.
Answer:v=0.4 m/s
Explanation:
Mass hockey player
mass of cup
Velocity of cup
let v be the velocity of the combined system
Conserving momentum