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3 years ago

How many miles of land area does a tower with a signal of 15 miles in all directions cover

Mathematics

2 answers:

Sliva [168]3 years ago

4 0

The area of a circle with a radius of 15 is about 707 or exactly 706.86

Degger [83]3 years ago

3 0

Such a tower covers a circle with center in the tower and radius 15 miles.

The area of a circle is $\pi r^2$ , so in your case it is

$A=\pi r^2 = \pi 15^2=225\pi$

If you need to approximate this number, recall that $\pi=3.1415\ldots$

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Simplify (3^5)^2/3^-2

Rasek [7]

Answer:

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Step-by-step explanation:

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3 years ago

The level of a lake was 8 inches below normal. It decrease 1 1/4 inches in June and 2 3/8 inches more in July. What was the new

zloy xaker [14]

Answer:

Step-by-step explanation:

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3 years ago

Find the greatest possible error for each measurement. 12.3 L

melisa1 [442]

Answer:

the GPE is 1/2 the unit of measure used to make the measurement or you say 1/2 the most precise unit

12.3 L has 0.1 as the most precise unit of measure, so 1/2 of 0.1 is 0.05 L which is c. above

look at it this way: 12.3 can be any number between 12.25 and 12.34 rounded to the nearest tenth

any number from 12.25 to 12.34 rounded to the nearest tenth gives you 12.3, so the GPE that you can possibly make is 0.05; if the number was 12.24 it would round down to 12.2 not up to 12.3 and if the number was 12.35 it would round up to 12.4 not round down to 12.3, so again the greatest possible error that you can make is 0.05

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2 years ago

What is 238 rounded to the nesrest ten

Solnce55 [7]

238 rounded to the nearest ten would be 240 because 8 is bigger than 5. So since its bigger we move the tens place (3) a number ahead (4).

Thats how we get 238 rounded to the nearest ten would be 240.

Hope I helped ya!!

6 0

3 years ago

Read 2 more answers

NO LINKS! Please help me with this problem

Dafna11 [192]

Answer:

$\frac{x^2}{9}+\frac{y^2}{4}=1$

Step-by-step explanation:

So an ellipse can be expressed in two different but very similar forms:

Horizontal Major Axis:

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$

Vertical Major Axis:
$\frac{(x-h)^2}{b^2}+\frac{(y-k)^2}{a^2}=1$

In both equations the length of the major axis is "2a" and the length of the minor axis is "2b"

In the equation you provided, the major axis is horizontal, and the minor axis is vertical.

So looking at the horizontal length, you can see that it's 6, and since this ellipse has a horizontal major axis, that means 2a=6, which means a=3

Looking at the vertical length, you can see that it's 4, and since the ellipse has a vertical minor axis, that means 2b=4, which means b=2

The last thing to note is that the center of an ellipse is (h, k) in the equation, and since here the center is (0, 0) it's (x-0)^2 and (y-0)^2 in the denominator which is just x^2 and y^2

So let's plug in the values into the equation:

$\frac{(x-h)^2}{a^2}+\frac{(y-k)^2}{b^2}=1$

(h, k) = (0, 0)

a = 3

b = 2

$\frac{x^2}{3^2}+\frac{y^2}{2^2}=1\\\\\frac{x^2}{9}+\frac{y^2}{4}=1$

7 0

2 years ago

Read 2 more answers