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Aleksandr-060686 [28]
4 years ago
7

PLease someone help me with these questions

Mathematics
1 answer:
expeople1 [14]4 years ago
8 0
I don’t know sorry I need help to maybe we can help each other
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john lee's savings account has a balance of $1509.After 9 years, what will the amount of interest be at 6% compounded annually?
serious [3.7K]

Answer: $2549

<u>Step-by-step explanation:</u>

A = P(1 + r)ˣ  ; where P is Principal, r is rate, and x is time

Given:

  • P = 1509
  • r = 6%  = 0.06
  • x = 9

A = 1509(1 + 0.06)⁹

   = 1509(1.06)⁹

   = 1509(1.6895)

   = 2549.42

7 0
3 years ago
Lease answer number 7 WILL GIVE BRAINLIEST
prohojiy [21]

Answer:

B

Step-by-step explanation:

hope this helps with the work

7 0
3 years ago
Read 2 more answers
2. Suppose that P(A) = 0.32, P(B) = 0.46, P(C) = 0.23, P(A ∪ B) = 0.57, P(A ∪ C) = 0.55, P(B ∪ C) = 0.49. a. Compute P(B ′ ). b.
Liula [17]

Answer:

Step-by-step explanation:

From the given information:

a.

Compute P(B'):

P(B') = 1 - P(B) \\ \\P(B') = 1 - 0.46 \\ \\ P(B') = \mathbf{0.54}

b.

Compute P(A ∩ B)

P(A ∩ B) =  P(A) +P(B) - P(A∪B)

P(A ∩ B) =  0.32 + 0.46 - 0.57

P(A ∩ B) =  0.21

Thus, since P(A ∩ B) ≠ 0, we can say that they are not mutually exclusive.

c.

P(A ∩ C) = P(A) +P(C) - P(A∪C)

P(A ∩ C) = 0.32 + 0.23 -0.55

P(A ∩ C) =  0

Thus, since P(A ∩ C) = 0, we can say that they are both mutually exclusive.

d. To determine  P[(A ∪ B ∪ C)′]

i.e. none of the events occurring

Then :

P(B ∩ C) = 0.46 +0.23 -0.49

P(B ∩ C) = 0.20

Therefore:

P(A ∪ B ∪ C) = P(A) + P(B) + P(C) - P(A ∩ B ) - P(A  ∩ C) - P(B ∩ C)  + P(A ∩ B ∩ C)

P(A ∪ B ∪ C) = 0.32 + 0.46 + 0.23 - 0.21 - 0 - 0.20 + 0

P(A ∪ B ∪ C) = 0.60

3 0
3 years ago
The great angle chase
Sedbober [7]
Yes the great angle chase is overpowered
3 0
3 years ago
Elijah was analyzing the trajectory made after throwing a football. His coach was able to measure that his throw reached a maxim
ziro4ka [17]

Answer:


Step-by-step explanation:

Given that Elijah threw a ball from a height of 4 feet.  The ball reached maximum height of 16 feet after 2seconds

Let vertical component of his speed be v

When it reaches maximum height its velocity becomes 0

Hence

height reached by the ball =h=vt-\frac{gt^2}{2}

When h=12(16-4) we get g=gravity =32

Hence 12 =2v-16(4)

v=38

Hence h=38t-\frac{32t^2}{2}

where h is calculated from the height of hand i.e. 4 feet

When it touches the ground h =-4

When it starts falling then distance travelled = 16 feet

Initial velocity =0 Accn due to gracity =32 feet

Using these we can write

16=0+\frac{32t^2}{2}\\ t=1

So after 3 minutes from start the ball would reach the ground



8 0
3 years ago
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