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2 years ago

Lexi runs a race at school. She runs at a rate of 4 miles

1 answer:

8 0

T=6x is the answer. For equations you always start with y which in this case is t, then 6 for miles per hour and then x

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Help me please <3<br><br> place <,>, or = in the blank <br> 17/2 ________√70

Georgia [21]

Answer:

Step-by-step explanation:

17/5 is 8.5 but √70 is 8.3 something that for 17/2>√70

7 0

3 years ago

Find the first three terms in the expansion , in ascending power of x , of (2+x)^6 and obtain the coefficient of x^2 in the expa

Nataly_w [17]

Answer:

The first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

coefficient of $x^{2}$ in the expansion of $(2+x - x^{2})^{6}$ = (240 - 192) = 48

Step-by-step explanation:

$(2+x)^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times x^{k} \times 2^{6 - k})$

= $6_{C_{0}} \times x^{0} \times 2^{6} + 6_{C_{1}} \times x^{1} \times 2^{5} + 6_{C_{2}} \times x^{2} \times 2^{4}$ + terms involving higher powers of x

= $64 + 192 \times x^{1} + 240 \times x^{2}$ + terms involving higher powers of x

so, the first 3 terms in the expansion of $(2 + x)^{6}$ , in ascending power of x are,

$64 , 192 \times x^{1} {\textrm{ and }}240 \times x^{2}$

Again,

$(2+x - x^{2})^{6}$

= $\sum_{k=0}^{6}(6_{C_{k}} \times (2 + x)^{k} \times (-x^{2})^{6 - k})$

Now, by inspection,

the term $x^{2}$ comes from k =5 and k = 6

for k = 5, the coefficient of $x^{2}$ is , $(-32) \times 6$ = -192

for k = 6 , the coefficient of $x^{2}$ is, $6_{C_{2}} \times 2^{4}$ = 240

so, coefficient of $x^{2}$ in the final expression = (240 - 192) = 48

3 0

2 years ago

What is 4 1/2 - 5 1/4?

alekssr [168]

Answer:

Step-by-step explanation:

well its 4.5-5.25= -0.75

7 0

3 years ago

Read 2 more answers

7. Ger and Amy are planting tulips. Ger has planted 60 tulips already and is planting more at a

artcher [175]

Answer:

23 hours

Step-by-step explanation: 44*32 = 1408 1408/60 = 23.46= 23 hours

3 0

2 years ago

Read 2 more answers

Combine Like Terms and Eliminate Parenthesis.<br>5z-[2z-(13z+8)]

katen-ka-za [31]

We need to start from the innermost parenthesis and work our way out.

The first parenthesis is $13z+8$ . These are not like terms because one involves a variable, while the other is a constant term. Two terms are summable if they involve the same power(s) of the same variable(s).

So, we can take one step outwards, and we arrive to the square brackets. We have

$2z-13z-8$

and 2z and -13z are like terms, so we can sum them:

$2z-(13z +8) = 2z-13z-8 = (2-13)z-8 = -11z-8$

Finally we arrive to the whole expression, which is

$5z-(-11z-8) = 5z+11z+8 = (5+11)z+8=16z+8$

Because, again, 5z and 11z were like terms.

6 0

3 years ago