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3 years ago

Solve the system of the following equations:

Mathematics

2 answers:

Alina [70]3 years ago

7 0

Answer:

$(5, \: - 2)$

Step-by-step explanation:

$x + 3y = - 1 \\ 2x + 2y = 6 \\ solve \: the \: equation \\ \\ x = - 1 - 3y \\ 2x + 2y = 6 \\ substitute \: the \: value \: of \: x \: into \: an \\ equation. \\ \\ 2( - 1 - 3y) + 2y = 6 \\ distribute \\ \\ - 2 - 6y + 2y = 6 \\ add \: - 6y \: to \: 2y \\ \\ - 2 - 4y = 6 \\ add \: 2 \: from \: both \: sides \\ \\ - 2y = 8 \\ divide \: both \: sides \: by \: 2 \\ \\ y = - 2 \\ substitute \: the \: value \: of \: y \: into \: an \\ equation. \\ \\ x = - 1 - 3( - 2) \\ distribute \\ \\ - 1 + 6 \\ add \: - 1 \: to \: 6 \\ \\ x = 5 \\ \\ (5, - 2)$

schepotkina [342]3 years ago

4 0

The answer is (5,-2)

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WITCHER [35]

Answer:

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3 years ago

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jeka57 [31]

Keywords:

<em>equation, operations, equivalent, binomial, square root </em>

For this case we have an equation in which we must apply operations to rewrite it in an equivalent way. We must start by raising both sides of the equation to the square. Thus, we eliminate the square root of the left side of equality and finally solve the binomial of the right side of equality.

So we have:

$\sqrt {x ^ 2 + 81} = x + 10\\(\sqrt {x ^ 2 + 81}) ^ 2 = (x + 10) ^ 2\\x ^ 2 + 81 = (x + 10) ^ 2$

By definition: $(a + b) ^ 2 = a ^ 2 + 2ab + b ^ 2$

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Answer:

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Option D

4 0

3 years ago

Read 2 more answers

ankoles [38]

Answer:

c) 5.39

Step-by-step explanation:

The digit that is in the hundredths place is the 8. (The hundredths are two digits to the right of the point).

The thousandths in this case would be the 9, since the 9 is close to the next hundredth, the nearest hundredth would be 9 (adding 1 to the 8), therefore the number would be 5.39

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