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KatRina [158]
3 years ago
6

Solute will continue to dissolve in a solvent until:

Chemistry
1 answer:
Gwar [14]3 years ago
6 0
The best and most correct answer among the choices provided by your question is the first choice or letter A.

<span>A solute will continue to dissolve in a solvent until an equilibrium is reached.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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All but one of the following is an important component of soil.
Sholpan [36]

Answer: B is the answer i believe.

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2 years ago
PLEASE HELP! I really don’t understand! Thanks!
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http://century.rochester.k12.mn.us/cms/One.aspx?portalId=3086882&pageId=6133921

Hope this helps!

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6 0
3 years ago
How much time would it take for 336 mg of copper to be plated at a current of 5.6 A ? Express your answer using two significant
schepotkina [342]

Answer:

1.8 × 10² s

Explanation:

Let's consider the reduction that occurs upon the electroplating of copper.

Cu²⁺(aq) + 2 e⁻ ⇒ Cu(s)

We will establish the following relationships:

  • 1 g = 1,000 mg
  • The molar mass of Cu is 63.55 g/mol
  • When 1 mole of Cu is deposited, 2 moles of electrons circulate.
  • The charge of 1 mole of electrons is 96,486 C (Faraday's constant).
  • 1 A = 1 C/s

The time  that it would take for 336 mg of copper to be plated at a current of 5.6 A is:

336mgCu \times \frac{1gCu}{1,000mgCu} \times \frac{1molCu}{63.55gCu} \times \frac{2mole^{-} }{1molCu} \times \frac{94,486C}{1mole^{-}} \times \frac{1s}{5.6C} = 1.8 \times 10^{2} s

3 0
3 years ago
Which set of elements have the most similar chemical properties?
EleoNora [17]

answer: A not sure but i hope it helps :) success

7 0
3 years ago
Be sure to answer all parts. For an aqueous solution of sodium chloride (NaCl), determine the molarity of 4.05 L of a solution t
SpyIntel [72]

Answer:

0.824\ \text{M}

5.62\ \text{L}

20.89\ \text{mol}

Explanation:

Molar mass of NaCl = 58.44 g/mol

Mass of NaCl = 195 g

Volume of solution = 4.05 L

Molarity of solution is

\dfrac{195}{4.05}\times \dfrac{1}{58.44}=0.824\ \text{M}

The molarity of the solution is 0.824\ \text{M}

Moles of NaCl = 4.63 mol

Volume is given by

\dfrac{4.63}{0.824}=5.62\ \text{L}

The volume of the solution that contains the required amount NaCl is 5.62\ \text{L}

Volume of solution = 25.35\ \text{L}

Moles of solution is given by

0.824\times 25.35=20.89\ \text{mol}

The number of moles of NaCl is 20.89\ \text{mol}.

6 0
3 years ago
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