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KatRina [158]
3 years ago
6

Solute will continue to dissolve in a solvent until:

Chemistry
1 answer:
Gwar [14]3 years ago
6 0
The best and most correct answer among the choices provided by your question is the first choice or letter A.

<span>A solute will continue to dissolve in a solvent until an equilibrium is reached.</span>

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
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The kinetic molecular theory states that all particles of an ideal gas are
Marizza181 [45]

THE KINETIC MOLECULAR THEORY STATES THAT ALL PARTICLES OF AN IDEAL GAS ARE IN CONSTANT MOTION AND EXHIBITS PERFECT ELASTIC COLLISIONS.

Explanation:

An ideal gas is an imaginary gas whose behavior perfectly fits all the assumptions of the kinetic-molecular theory. In reality, gases are not ideal, but are very close to being so under most everyday conditions.

The kinetic-molecular theory as it applies to gases has five basic assumptions.

  • Gases consist of very large numbers of tiny spherical particles that are far apart from one another compared to their size.
  • Gas particles are in constant rapid motion in random directions.
  • Collisions between gas particles and between particles and the container walls are elastic collisions.
  • The average kinetic energy of gas particles is dependent upon the temperature of the gas.
  • There are no forces of attraction or repulsion between gas particles.
5 0
3 years ago
Aluminum finds application as a foil for wrapping food stuves. Why?
pshichka [43]

Answer:

it keeps the heat in and the bugs and flys out

Explanation:

8 0
1 year ago
PLEASE HELP WILL GIVE BRAINLIEST
bija089 [108]

Answer:

sorry i'm not a scientist but i think it's C

Explanation:

sorry again if i get it wrong for u :(

3 0
3 years ago
How many grams of the excess reactant are left over according to the reaction below given that you start with 10.0 g of Al and 1
valentinak56 [21]
<span>4 Al + 3 O2 → 2 Al2O3 

(10.0 g Al) / (26.98154 g Al/mol) = 0.37062 mol Al 
(19.0 g O2) / (31.99886 g O2/mol) = 0.59377 mol O2 

0.37062 mole of Al would react completely with 0.37062 x (3/4) = 0.277965 mole of O2, but there is more O2 present than that, so O2 is in excess. 

((0.59377 mol O2 initially) - (0.277965 mol O2 reacted)) x (31.99886 g O2/mol) = 
10.1 g O2 left over</span><span>
</span>
7 0
3 years ago
Read 2 more answers
PLEASE HELP I DONT WANT TO FAIL!! ):
Fudgin [204]
Hope this helps :) I didn’t know how to write subscripts so I wrote it down on some paper.

3 0
3 years ago
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