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Tanya [424]
3 years ago
15

Which of the following is necessary to increase the rate of a reaction?

Chemistry
1 answer:
irga5000 [103]3 years ago
6 0
Rate of Reaction ca be increased by applying following changes,

1) Increase in Temperature:
                                            Increase in Temperature results in the increase of Kinetic Energy, Hence, velocity of reactants increases and rate of collisions increases. Thus, more reactants colloid with enough energy to change into products in given time.

2) Decrease in Activation Energy:
                                                     Activation energy is the minimum amount of energy required by reactants to cross the energy barrier to convert into products. Hence, activation energy is decreased by using catalyst.

3) Concentration of Reactants:
                                                 The greater the concentration of reactants, greater is the number of reactants per volume. More reactants in less area increase the probability of collision. Hence, collisions increase and rate of reaction increases.

4) Increasing Surface Area of Reactant:
                                                               Greater the surface area greater is the rate of reaction.
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3 years ago
If 25.8 grams of BaO dissolve in enough water to make a 212-gram solution, what is the percent by mass of the solution?
Igoryamba
The correct answer is 12.2% BaO.

The solution is found by dividing the mass of the BaO, which is 25.8 grams, by the total mass of the solution, which is 212 grams, then multiplying it by 100 to get the percentage:
\frac{25.8}{212}*(100) =12.2%
3 0
3 years ago
Solar System Web quest Name: Addison Thurman Class Period: 2nd
Ksivusya [100]
Are you kidding me is this answer or question you got be kidding
5 0
3 years ago
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A solution is prepared by dissolving 2.61 g ethanol (C2H5OH) in 16.2 g water. What is the molality (mol/kg) of C2H5OH in the sol
stiks02 [169]

Answer:

3.50 molal

Explanation:

Molality → Moles of solute / kg of solvent.

Let's convert the solvent's mass from g to kg

16.2 g . 1kg / 1000 g = 0.0162 kg

Let's determine the moles from the solute

2.61 g . 1 mol / 46 g = 0.0567 moles

Molality → 0.0567 mol / 0.0162 kg = 3.50 m

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Butoxors [25]

Answer:

I think option A is right answer

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