Step-by-step explanation:
Let the height above which the ball is released be H
This problem can be tackled using geometric progression.
The nth term of a Geometric progression is given by the above, where n is the term index, a is the first term and the sum for such a progression up to the Nth term is
To find the total distance travel one has to sum over up to n=3. But there is little subtle point here. For the first bounce ( n=1 ), the ball has only travel H and not 2H. For subsequent bounces ( n=2,3,4,5...... ), the distance travel is 2×(3/4)n×H
a=2H..........r=3/4
However we have to subtract H because up to the first bounce, the ball only travel H instead of 2H
Therefore the total distance travel up to the Nth bounce is
For N=3 one obtains
D=3.625H
-18f - 34 - 14f = 11
-32f - 34 = 11
-32f = 45
f = -32/45
Simplify the fraction if needed!
Hope this helps, and please mark brainliest!
To answer this question with the choices given, you would substitute the possible answers into your work for the base and the height of each dimension on the entire campground.
To find the length of the campground, you multiply each choice by 5 because there are 5 campsites.
For the width, you add each choice to 4.
Then you multiply the total length by the total width to see if your answer is 950 square yards.
See the attached picture for all the work.
9.125*x^2 is 100000 times greater than 9.125*10^(-3).
Note that (10^5)(9.125*10^(-3) = 9.125*10^2.