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Bogdan [553]
3 years ago
10

I don’t how to woke this

Physics
1 answer:
NeX [460]3 years ago
3 0
Use the calculator to find out the answer
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What is a hypothesis
notsponge [240]
A hypothesis can be described as an intelligent guess 
7 0
3 years ago
How long will it take you to travel 20 miles on a bus that drives 60 miles/h?
ValentinkaMS [17]

Answer:

<u>20 Minutes</u>

<u></u>

Explanation:

Well we know Mph (Miles per hour) is distance over time : \frac{distance}{time} \\

R (rate) = 60

d (distance) = 20

t (time) = Unknown

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

 R = \frac{d}{t}  

   ↓

60 = \frac{20}{t}

   ↓

 t = \frac{20}{60}

    ↓

 t = \frac{1}{3}  or 0.3333

<em>So basically it would take one third of an hour. Lets change these units to minutes.</em>

60 * 0.333333 = 20

<em>So it would take you </em><u><em>20 minutes</em></u><em> to drive 20 miles on a bus that drives 60 mph</em>

<em />

Hope that helps

<em>~Siascon~</em>

8 0
3 years ago
Eukaryotic that can reproduce sexually contain two types of cells
Darina [25.2K]
<span>Only eukaryotes form multicellular organisms consisting of many kinds of tissue made up of different cell types. Eukaryotes can reproduce both asexually through mitosis and sexually through meiosis and gamete fusion. In mitosis, one cell divides to produce two genetically identical cells.</span>
7 0
3 years ago
Which ramp requires the least amount of force?
irinina [24]
Length 4ft height 1ft
5 0
2 years ago
In a 100 mm diameter horizontal pipe, a venturimeter of 0.5 contraction ratio has been fitted. The head of water on the meter wh
horrorfan [7]

Answer:

the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

Explanation:

Given:

Diameter of the pipe = 100mm = 0.1m

Contraction ratio = 0.5

thus, diameter at the throat of venturimeter = 0.5×0.1m = 0.05m

The formula for discharge through a venturimeter is given as:

Q=C_d\frac{A_1A_2}{\sqrt{A_1^2-A_2^2}}\sqrt{2gh}

Where,

C_d is the coefficient of discharge = 0.97 (given)

A₁ = Area of the pipe

A₁ = \frac{\pi}{4}0.1^2 = 7.85\times 10^{-3}m^2

A₂ = Area at the throat

A₂ = \frac{\pi}{4}0.05^2 = 1.96\times 10^{-3}m^2

g = acceleration due to gravity = 9.8m/s²

Now,

The gauge pressure at throat = Absolute pressure - The atmospheric pressure

⇒The gauge pressure at throat = 2 - 10.3 = -8.3 m (Atmosphric pressure = 10.3 m of water)

Thus, the pressure difference at the throat and the pipe = 3- (-8.3) = 11.3m

Substituting the values in the discharge formula we get

Q=0.97\frac{7.85\times 10^{-3}\times 1.96\times 10^{-3}}{\sqrt{7.85\times 10^{-3}^2-1.96\times 10^{-3}^2}}\sqrt{2\times 9.8\times 11.3}

or

Q=\frac{0.97\times15.42\times 10^{-6}\times 14.88}{7.605\times 10^{-3}}

or

Q = 29.28 ×10⁻³ m³/s

Hence, the rate of flow = 29.28 ×10⁻³ m³/s or 0.029 m³/s

5 0
3 years ago
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