Question

1. Determine the magnitude of two equal but opposite charges if they attract one another with a force of 0.7N when at distance of 0.3m apart in a vacuum.​

Answer 1

Answer:

q = 2.65 10⁻⁶ C

Explanation:

For this exercise we use Coulomb's law

        F =$k \frac{q_1q_2}{r^2}$

In this case they indicate that the load is of equal magnitude

       q₁ = q₂ = q

the force is attractive because the signs of the charges are opposite

       F = $k \ \frac{q^2}{r^2}$

       q = $\sqrt{\frac{F \ r^2}{k} }$

we calculate

        q = $\sqrt{\frac{0.7 \ 0.3^2 }{9 \ 10^9} }$

        q = $\sqrt{7 \ 10^{-12} }$Ra 7 10-12

        q = 2.65 10⁻⁶ C