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LenKa [72]
3 years ago
6

If the pressure on 36.0 milliliters of a gas at STP is changed to a pressure of 25.3 kPa at constant temperature, the new volume

of the gas is
Chemistry
2 answers:
mart [117]3 years ago
8 0

0.144 litres or 144 ml is the volume f the pressure on 36.0 milliliters of a gas at STP is changed to a pressure of 25.3 kPa at constant temperature.

Explanation:

data given:

initial volume of gas = 36 ml 0r 0.036 litres

initial pressure at STP = 1 atm

final volume of the gas=?

final pressure = 25.3 kpa or 0.249 atm

Applying the Boyle's Law:

P1V1 = P2V2

0.036 X 1 = x X 0.249

X = 0.144 LITRES.

the volume of the gas is 0.144 litres.

The units are changed to to ml by multiplying it with 1000 so 144 ml is the volume of the gas.

Cloud [144]3 years ago
5 0

The new volume of the gas is 144 mL.

<u>Explanation:</u>

At STP, the temperature is 273 K an pressure is 1 atm.

1 atm=101kPa

Given that initial volume V1=36 mL

Initial pressure P1=1atm=101 kPa

Final pressure P2=25.3kPa

We have to determine the final volume V2

According to Boyle's law

P_{1} V_{1} =P_{2} V_{2}

V_{2} =P_{1} V_{1} /P_{2}

=25.3\times101/25.3

=144 mL

Final volume =144mL

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Determine the location of the last significant place value by placing a bar over the digit.
Vlad1618 [11]

Answer:

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699.5  

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90, 100  

4.7 x 10-8  

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Explanation:

First remember the following rules of determining the last significant place value :

1. The digits from 1-9 are all significant and zeros between significant digits are also significant.

2.  The trailing or ending zeroes are significant only in case of a decimal number otherwise they are ignored. However starting zeroes of such a number are not significant.

Now observing above rules, lets determine the location of the last significant place value of each given example. I am determining the location by turning the last significant place to bold.

1) 8,040

8,040

Location of the last significant place value is 3 and bar is over last significant digit that is 4. Number is not decimal so ending zero is ignored. Every non zero digit is a significant.

2)  0.0300

0.0300

Location is 3 and bar is over 0. Number has a decimal point so ending zero is not ignored but starting zeroes are ignored.

3) 699.5

699.5

Location is 4 and bar is over 5.

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200.0 so last significant digit is 0 and location of last significant digit is 4.

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Location is 3 and bar is over 1. This is because it is not a number with decimal point. So the trailing zeroes are ignored. The count starts from 9 and last significant is 1.

7) 4.7 x 10⁻⁸

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Location is 2 and bar is over 7. This is because the starting zeroes in a number with a decimal point are ignored. So the first digit considered is 4 and last significant digit is 7. If we expand this number:

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Here the starting zeroes are ignored because there is a decimal point in the number.

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Location is 9 and bar is over 0.  Number has a decimal point so ending zero is not ignored and last significant figure is 0.

However if the number is like:

10,800,000. Then location would be 8 and bar is over 0.

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Location is 3 and bar is over 1. Lets expand this number first

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So this is the number:

3010000000000000000000

Since this is number does not have a decimal point so the trailing zeroes are ignored. Hence the count starts from 3 and the last significant figure is 1

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Location is 3 and bar is over 0. This is because the number has a decimal point so the ending zero is not ignored but the starting zeroes are ignored according to the rules given above. Hence the first significant figure is 4 and last significant figure is 0.

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