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d1i1m1o1n [39]
3 years ago
7

Trigonal planars have a 180 degree bond angle but do bent trigonal planars also have a 180 degree bond angle? Thank you ^^

Chemistry
2 answers:
Yanka [14]3 years ago
8 0

Answer:


The ideal bond angle is 120°, but the real bond angle of bent molecules is usually a few degrees less.


Explanation:


The bonds of a trigonal planar AX₃ molecule point toward the corners of an equilateral triangle.


They trisect a circle into three angles of 120° each.


An example is BF₃ (Figure 1). It is perfectly symmetrical, so the F-B-F bond angles are exactly 120°.


===============


Now, consider ozone (Figure 2).


The two O-O bonds are equivalent because of resonance.


There are two bonding groups and a lone pair, for a total of three electron groups.


The electron geometry is trigonal planar, and the molecular shape is bent.


However, the lone pair occupies more space than the bonding electrons.


It repels the bolding electrons, so the O-O-O bond angle is 116°, slightly less than the ideal angle of 120°.


earnstyle [38]3 years ago
8 0

trigonal planar means the molecule is planar n has a triangular shape. bond angle = 360/2 = 120deg.

bent trigonal planar means the molecular shape has been bent by some forces n its bond angle is no longer 120deg.


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A 0.533 g sample of a carbonate salt is added to a flask. The only thing you know is that per formula unit, there is only one ca
dimulka [17.4K]

Answer:

\mathbf{CrCO_3}

Explanation:

The total mole of H_2SO_4 added = 15 × 1 × 10⁻³

= 15 × 10⁻³ mole

= 15 mmoles

the number of moles of NaOH added in order to neutralize the excess acid = 0.5905 ×  29.393 = 17.36 mmoles

the equation for the reaction is:

2NaOH + H_2SO_4 --------> Na_2SO_4 +2H_2O

i.e

2 moles of NaOH react with H_2SO_4

1 moles of  NaOH will react with 1/2  H_2SO_4

17.36 mmoles of NaOH = 1/2 × 17.36 mmoles of H_2SO_4

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Number of moles of H_2SO_4 that react with MCO₃ = Total moles of H_2SO_4 added - moles of H_2SO_4 reacted with NaOH

= (15 - 8.68) mmoles

= 6.32 mmoles

H_2SO_4 + MCO_3  ------>   M_2SO_4   +    H_2O   +   CO_2

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We all know that ;

number of moles = mass/molar mass

Then:

6.32 10⁻³ = 0.533 / (M+60)

(M+60) = 0.533/ 6.32 10⁻³

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M = 84.34 - 60

M = 24.34

Thus the element with the atomic mass of 24.34 is Chromium

The chemical formula for the compound is :  \mathbf{CrCO_3}

6 0
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