3 years ago

I need alot of help.

Chemistry

1 answer:

GaryK [48]3 years ago

6 0

Of course! I can help, what is it that you need help on and I shall try my best to answer!

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Peter is 5 ft, 11 inches tall. Paul is 176 cm tall. Who is taller?

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Calculate the energy required to heat 406.0mg of cyclohexane from 33.5°C to 38.9°C . Assume the specific heat capacity of cycloh

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Answer:

Q = 4.056 J

Explanation:

Q = m<em>C</em>ΔT

∴ m = 406.0 mg = 0.406 g

∴ <em>C </em>= 1.85 J/g.K

∴ T1 = 33.5°C ≅ 306.5 K

∴ T2 = 38.9°C = 311.9 K

⇒ ΔT = 311.9 - 306.5 = 5.4 K

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A. Boiling point = 59 °C, Melting point = -7.2°C, triple point = -7.3°C

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Vertical columns in the periodic table indicate what information? . . . A.. periods. . . B.. liquids. . . C.. synthetic elements

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4. Ammonium nitrate (NH4NO3) fertilizer decomposes explosively into gaseous nitrogen, oxygen, and water, resulting in huge therm

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Answer:

280 g

Explanation:

Let's consider the decomposition of ammonium nitrate.

NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)

We can establish the following relations:

The molar mass of NH₄NO₃ is 80.04 g/mol.
The molar ratio of NH₄NO₃ to N₂ is 1:1.
The molar mass of N₂ is 28.01 g/mol.

The mass of N₂ produced when 800 g of NH₄NO₃ react is:

$800gNH_{4}NO_{3}.\frac{1molNH_{4}NO_{3}}{80.04gNH_{4}NO_{3}} .\frac{1molN_{2}}{1molNH_{4}NO_{3}} .\frac{28.01gN_{2}}{1molN_{2}} =280gN_{2}$

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3 years ago