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Reil [10]
3 years ago
13

What two quantities must stay the same in order for an object to have a constant velocity? A) The speed and kinetic energy must

be constant. B) The speed and mass of the object must be constant. C) The speed and direction of travel must be constant. D) The force applied to and direction of travel must be constant.
Physics
1 answer:
GarryVolchara [31]3 years ago
7 0

the answer is c) the speed and direction of travel must be constant


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Kinetic friction is affected by the weight of the object. True or false?
nevsk [136]

True Kinetic friction is affected by the weight of the object

3 0
3 years ago
What is the mass of a car that weighs 19,000 N on earth?
Anna71 [15]
Divide by 9.8 I think
 so <span>1938.77551</span>
8 0
3 years ago
when two resistors are wired in series with a 12 v battery, the current through the battery is 0.31 a. when they are wired in pa
liberstina [14]

Let  R₁  and R₂ be the  two Resistance

R₁ - Resistance of 1st resistor

R₂ - Resistance of 2nd resistor

V = Voltage = 12V

I = O.31A ( in series)

I  = 1.6 A ( in parallel)

when two resistance connected in series

Rs = R₁ + R₂

V = IRs = 12 /0.31 V

R₁+R₂ = 38.700Ω   (equation1.)

When two resistance connected in parallel

    R_{p} =\frac { R_{1} R_{2}}{R_{1} + R_{2}  }

V = I Rp

V=  I (R₂ R₁ /R₁ +R₂)

R₁ R₂ = 290.25 Ω  

As we know

(R₁ - R₂ ) ² = (R₁ + R₂ ) ² - 4R1R2

Using above values we get,

 (R₁ - R₂ ) ²  = (38.70) ²  - 4x 290.25

 (R₁ - R₂ ) ²   = 336.69  Ω  

R₁ - R₂ = 18.34     (equation 2 )

Using equation 1 and 2 we get

R₁+ R₂ = 38.70 52

R₁ - R₂ = 18.34

R₁ = 28.535 Ω  

Using the value of  R₁ in equation 1 we get

R₂ = 38·700 -  28.535

RR₂ = 10.125 Ω  

R₁ = 28. 535 v  and   R₂  10.125 Ω  

To know more about resistance in series and parallel:

brainly.com/question/27882579

#SPJ4

7 0
1 year ago
A thin, metallic spherical shell of radius 0.187 m has a total charge of 6.53×10−6 C placed on it. A point charge of 5.15×10−6 C
MAVERICK [17]

Answer: a) 112.88 * 10^3 N/C; b) The electric field point outward from the center of the sphere.

Explanation: In order to solve this problem we have to use the gaussian law so we use a gaussian surface at r=0.965 m and the electric flux is equal to Q inside/εo

E* 4*π*r^2= Q inside/εo

E= k*Q inside/r^2= 9*10^9*(6.53+5.15)μC/(0.965)^2=122.88 * 10 ^3 N/C

5 0
3 years ago
Two organ pipes, both open at one end but closed at the other, are each 1.14 m long. One is now lengthened by 2 cm. Find the fre
zloy xaker [14]

Answer: 1.3 Hz

Explanation:

4 0
3 years ago
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