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-Dominant- [34]
2 years ago
6

What is the most interesting or surprising thing you learned about contact and non-contact forces?

Physics
2 answers:
beks73 [17]2 years ago
4 0

Answer:

nothing interest, i just hate that part i love only the calculations

Deffense [45]2 years ago
4 0

Answer:

yo mom jumping on me cuz of gravity

Explanation:

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A block of mass 500g is pulled from rest on ahorizontal frictionless bench by a steady force F and travels 8m in 2s find the acc
Korvikt [17]

<u>We are Given:</u>

Mass of the block (m) = 500 grams or 0.5 Kg

Initial velocity of the block (u) = 0 m/s

Distance travelled by the block (s) = 8 m

Time taken to cover 8 m (t)= 2 seconds

Acceleration of the block (a) = a m/s²

<u>Solving for the acceleration:</u>

From the seconds equation of motion:

s = ut + 1/2* (at²)

<em>replacing the variables</em>

8 = (0)(2) + 1/2(a)(2)²

8 = 2a

a = 4 m/s²

Therefore, the acceleration of the block is 4 m/s²

3 0
3 years ago
The Sun is about 150 million km from earth. how long does it take light from the sun to reach earth? (Speed of light is 3x10^8m/
madam [21]

Time  =        (distance) / (speed)

Time  =  (150 x 10⁹ m) / (3 x 10⁸ m/s) =

                           50 x 10¹ sec  = 

                                 <em>500 sec</em>  =  8 min 20 sec


3 0
4 years ago
True or False: It would be easier to run on a planet with high gravity than one with less gravity.
LUCKY_DIMON [66]
True! It would be easier
3 0
3 years ago
Someone can help me?
boyakko [2]
<h3>When the object is placed at a further distance from the center of the mirror's curvature (twice the focal length), we will get a thumbnail</h3><h3 /><h3>position of the image from the mirror; Between focus and center of curvature of the mirror (double focal length)</h3><h3 /><h3> picture description; real, inverted, mini</h3>

<h3>* This picture is to draw the rays, just replace the candle with an apple .</h3>

<h3>Do you want me to write it in Spanish to help you?? ^_^</h3>

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8 0
3 years ago
A bicycle rider pushes a 13kg bicycle up a steep hill. the incline is 24 degree and the road is 275m long. the rider pushes the
Digiron [165]

Answer:

A. W = 6875.0 J.

B. W = -14264.6 J.

Explanation:

A. The work done by the rider can be calculated by using the following equation:

W_{r} = |F_{r}|*|d|*cos(\theta_{1})

Where:                

F_{r}: is the force done by the rider = 25 N

d: is the distance = 275 m

θ: is the angle between the applied force and the distance

Since the applied force is in the same direction of the motion, the angle is zero.

W_{r} = |F_{r}|*|d|*cos(0) = 25 N*275 m = 6875.0 J

Hence, the rider does a work of 6875.0 J on the bike.

B. The work done by the force of gravity on the bike is the following:

W_{g} = |F_{g}|*|d|*cos(\theta_{2})  

The force of gravity is given by the weight of the bike.

F_{g} = -mgsin(24)     

And the angle between the force of gravity and the direction of motion is 180°.

W_{g} = |mgsin(24)|*|d|*cos(\theta_{2})  

W_{g} = 13 kg*9.81 m/s^{2}*sin(24)*275 m*cos(180) = -14264.6 J  

The minus sign is because the force of gravity is in the opposite direction to the motion direction.

Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.  

I hope it helps you!                                                                                          

3 0
3 years ago
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