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3 years ago

9

Si m1 es 6kg y m2 es 14kg y la masa de la polea es despreciable ¿Cual es la aceleración que adquiere el sistema?

1 answer:

Annette [7]3 years ago

8 0

Answer:

Please transilate

Explanation:

I didn't get it

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What is formed when sediment stick together

Taya2010 [7]

Think its either sedimentary rocks or metamorphic rocks.

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3 years ago

The volume of a gas is reduced when the temperature is decreased

Sloan [31]

Decreasing Pressure. The combined gas law states that the pressure of a gas is inversely related to the volume and directly related to the temperature. If temperature is held constant, the equation is reduced to Boyle's law. Therefore, if you decrease the pressure of a fixed amount of gas, its volume will increase.

8 0

3 years ago

As a 15000 kg jet plane lands on an aircraft carrier, its tail hook snags a cable to slow it down. The cable is attached to a sp

RideAnS [48]

Answer:

60 m/s

Explanation:

From the law of conservation of energy,

The kinetic energy of the plane = Energy of store in the spring when the plane lands.

1/2mv² = 1/2ke²

making v the subject of the equation.

v = √(ke²/m).................... Equation 1

Where v = the plane landing speed, k = spring constant, e = extension. m = mass of the plane.

Given: m = 15000 kg, k = 60000 N/m, e = 30 m.

Substitute into equation 1

v = √(60000×30²/15000)

v = √(4×900)

v = √(3600)

v = 60 m/s.

Hence the plane's landing speed = 60 m/s

5 0

3 years ago

A proton (mass m = 1.67 × 10-27 kg) is being accelerated along a straight line at 2.50 × 1012 m/s2 in a machine. If the proton h

Veronika [31]

Answer:

(A) Speed will be $44.18\times 10^4m/sec$

(b) Change in kinetic energy = $1560\times 10^{-19}$

Explanation:

We have given mass of proton $m=1.67\times 10^{-27}kg$

Acceleration of the proton $a=2.50\times 10^{12}m/sec^2$

Initial velocity u = $1.60\times 10^4$ m/sec

Distance traveled by proton s = 3.90 cm = 0.039 m

(a) From third equation of motion we know that

$v^2=u^2+2as$

$v^2=(1.60\times 10^4)^2+2\times 2.5\times 10^{12}\times 0.039$

$v=44.18\times 10^4m/sec$

(b) Initial kinetic energy $KE_I=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (1.6\times 10^4)^2$

Final kinetic energy $KE_F=\frac{1}{2}mv^2=\frac{1}{2}\times 1.67\times 10^{-27}\times (44.18\times 10^4)^2$

So change in kinetic energy $\Delta KE=KE_F-KE_I=\frac{1}{2}\times 1.6\times 10^{-27}\times 10^8\times (44.18^2-1.6^2)=1560\times 10^{-19}J$

6 0

3 years ago

These types of electromagnetic waves are listed in order of increasing frequency:

xenn [34]

Answer:

B. X-rays

Explanation:

From the given choices, x-rays will have the highest energy of the given waves.

The energy of electromagnetic waves is highly dependent on their frequency and wavelength.

Electromagnetic waves with a high frequency and small wavelength will have higher energy compared to those with low frequency and high wavelength.

X-rays are one the most energetic waves on the periodic table. They have a very high frequency and low wavelength.

7 0

3 years ago

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