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laiz [17]
3 years ago
9

Si m1 es 6kg y m2 es 14kg y la masa de la polea es despreciable ¿Cual es la aceleración que adquiere el sistema?

Physics
1 answer:
Annette [7]3 years ago
8 0

Answer:

Please transilate

Explanation:

I didn't get it

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What forces act upon the moon as it orbits the earth
ValentinkaMS [17]

the axis acts against and it would be a contact force



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3 years ago
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A tiger runs at 58 km/h [S]. What is the displacement of the tiger in 38 s?
Artyom0805 [142]
58 K/h = 58000/3600= 16.1 m/s
In 38 s displacement is 38x16.1= 612.2 m
3 0
3 years ago
Which planet is least like earth? Mars,Venus, or Jupiter
Brums [2.3K]

Answer:

mars, reason why is because they both are diff from the size

Explanation:

7 0
3 years ago
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A) A mass spectrometer has a velocity selector that allows ions traveling at only one speed to pass with no deflection through s
KengaRu [80]

Answer:

(A). The speed of the ions is 1.2\times10^{6}\ m/s

(B). The radius of curvature of a singly charged lithium ion is 2.0\times10^{6}\ m

Explanation:

Given that,

Electric field = 60000 N/C

Magnetic field = 0.0500 T

(A). We need to calculate the velocity

For no deflection

F_{E}=F_{B}

Eq=Bqv

v = \dfrac{E}{B}

v=\dfrac{60000}{0.0500}

v=1.2\times10^{6}\ m/s

(B). We need to calculate the radius

Using magnetic force balance by centripetal force

Bqv=\dfrac{mv^2}{r}

r=\dfrac{mv^2}{Bqv}

Put the value into the formula

r=\dfrac{1.16\times10^{-26}\times(1.2\times10^{6})^2}{0.0500\times1.6\times10^{-19}}

r=2.0\times10^{6}\ m

Hence, (A). The speed of the ions is 1.2\times10^{6}\ m/s

(B). The radius of curvature of a singly charged lithium ion is 2.0\times10^{6}\ m

6 0
3 years ago
A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.
jeka94
  • Mass of the elevator (m) = 570 Kg
  • Acceleration = 1.5 m/s^2
  • Distance (s) = 13 m
  • Let the force be F.
  • We know, F = ma,
  • Therefore, F = (570 × 1.5) N = 855 N
  • Angle between distance and force (θ) = 0°
  • We know, work done = F s Cos θ
  • Therefore, work done by the cable during this part
  • = (855 × 13 × Cos 0°) J
  • = (855 × 13 × 1) J
  • = 11115 J

<u>Answer</u><u>:</u>

<u>1</u><u>1</u><u>1</u><u>1</u><u>5</u><u> </u><u>J</u>

Hope you could get an idea from here.

Doubt clarification - use comment section.

6 0
2 years ago
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