Si m1 es 6kg y m2 es 14kg y la masa de la polea es despreciable ¿Cual es la aceleración que adquiere el sistema?

If the displacement of a horizontal mass-spring system was doubled, the elastic potential energy in the system would change by a

bixtya [17]

Answer:

K'=4K

Explanation:

The electric potential energy is given by :

$E=\dfrac{1}{2}kx^2$

Where

k is spring constant

x is compression or extension in the spring

If the displacement of a horizontal mass-spring system is doubled, x'= 2x

New elastic potential energy :

$E'=\dfrac{1}{2}kx'^2\\\\E'=\dfrac{1}{2}k(2x)^2\\\\=\dfrac{1}{2}k\times 4x^2\\\\K'=4\times \dfrac{1}{2}kx^2\\\\K'=4K$

So, new elastic potential energy 4 times the initial elastic potential energy.

3 0

2 years ago

An astronaut travels to a star system 3.9 lyly away at a speed of 0.90 cc . Assume that the time needed to accelerate and decele

kakasveta [241]

Total time elapsed is =8.2y

The starting event is the astronaut leaving Earth. The finishing event is the astronaut arriving at the star system. The time between these events on Earth is:

Δt=3.9ly/0.9c

Δt=4.3y

For the astronaut, two events occur at the same position and can be measured with just one clock. Hence,

Δτ

$= \sqrt{1 - \frac{v {}^{2} }{c {}^{2} } } \times Δt$

Δτ

$= \sqrt{1 - ( \frac{0.9c}{c} ) {}^{2} } \times (4.3y)$

Δτ=1.8ly

The total elapsed time is:

T elapsed=Δt+3.9

T elapsed=4.3+3.9

T elapsed=8.2y

learn more about time from here: brainly.com/question/28208983

#SPJ4

4 0

1 year ago

A flying saucer moving initially at 20 m/s[E] accelerates to 50 m/s[W] in 3.8 s. Find the saucer's average

Rashid [163]

Answer:A flying saucer moving initially at 20 m/s[E] accelerates to 50 m/s[W] in 3.8 s. Find the saucer's average

acceleration during the time interval.

22. Two arrows are launched at the same time with the same speed of 10 m/s. Arrow A is launched at an angle of 65 degrees, and arrow B at an angle of 25 degrees. Both land at the same spot on the horizontal ground. Ignore air resistance and the height of the archet How long does it take for both arrows to land on the ground?

*Our experts’ time to respond varies by subject and question (we average 46 mins)

**Content not available for all Textbook Solutions or subjects

Explanation:

8 0

2 years ago

A time-dependent but otherwise uniform magnetic field of magnitude B0(t) is confined in a cylindrical region of radius 6.5 cm. I

vodka [1.7K]

Answer:

a = 603.59 m/s^2

Explanation:

from the data given . the rate of change in magnetic field is as follow

$\frac{dB}{dt} = 280 G/s = 280 \times 10^{-4} T/s$

from the faraday's law of induction , the expression for the induced emf in region of radius r as follow

$\epsilon = \frac{d \phi}{dt}$

$\int E.dl = \frac{d(BA)}{dt}$

$E(2\pi r)= \pi r^2 \frac{dB}{dt}$

$E = \frac{r}{2} \frac{dB}{dt}$

electric field at point P_1 as follow

$E = \frac{r}{2} \frac{dB}{dt}$

$E = \frac{1.5\times 10^{-2}}{2} 280 \times 10^{-4}$

$E = 6.3\times 10^{-6} V/m$

from newton 2nd law of motion, the acceleration of proton is

F = ma

qE = ma

$a = \frac{qE}{m}$

$a = \frac{1.6 \times 10^{-19} (6.3\times 10^{-6})}{1.67\times 10^{-27}}$

a = 603.59 m/s^2

5 0

2 years ago

What effect does the removal of vegetation have on soil ?

Strike441 [17]

Hello!

The removal of vegetation causes the desertification and erosion of soil. The roots of the plants that are inside the soil create a sort of net that prevents the material to be dragged by the water from the rain. They also absorb any excess water that can weaken the soil structure. If vegetation is removed from the soil, the nutrients can be dragged by water currents and slowly the desertification will occur.

Have a nice day!

5 0

2 years ago