Answer : The value of
at this temperature is 66.7
Explanation : Given,
Pressure of
at equilibrium = 0.348 atm
Pressure of
at equilibrium = 0.441 atm
Pressure of
at equilibrium = 10.24 atm
The balanced equilibrium reaction is,

The expression of equilibrium constant
for the reaction will be:

Now put all the values in this expression, we get :


Therefore, the value of
at this temperature is 66.7
The answer is c)11 because copper has 11 valence electrons
The answer is dissolved in water, because in chemistry, (aq) is shorthand for aqueous solution.
Answer: Li is the reducing agentg and O is the oxidizing agent.
Explanation:
1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.
2) The given reaction is:
4Li(s) + O₂ (g) → 2 Li₂O(s)
3) Determine the oxidation states of each atom:
Li(s): oxidation state = 0 (since it is alone)
O₂ (g): oxidation state = 0 (since it is alone)
Li in Li₂O (s) +1
O in Li₂O -2
That because 2× (+1) - 2 = 0.
4) Determine the changes:
Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.
O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.
PH = -log[H+]
pH = -log[1,7×10^-9]
pH = 8,77
pH + pOH = 14
pOH = 14 - 8,77
pOH = 5,23