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GREYUIT [131]
3 years ago
11

Select the conjugate acid-base pair(s). a) HI, I b) HCHO2, SO4^2- c) CO3^2-, HCI d) PO4^3-, HPO4^2-

Chemistry
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

PO4^3-, HPO4^2-

Explanation:

If an acid gives out a proton, the acid then changes to its corresponding base. Similarly, if a base takes in a proton, it changes to its corresponding acid. If a pair of acid and base differ only by the presence or absence of a proton, then they are referred to as a conjugate acid-base pair.

Let us look at this;

HPO4^2-(aq) ----> H^+(aq) + PO4^3-(aq)

HPO4^2- and PO4^3- differ only in the presence or absence of a proton (H^+) hence they constitute a conjugate acid-base pair.

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Phosphorous trichloride and phosphorous pentachloride equilibrate in the presence of molecular chlorine according to the reactio
umka21 [38]

Answer : The value of K_p at this temperature is 66.7

Explanation : Given,

Pressure of PCl_3 at equilibrium = 0.348 atm

Pressure of Cl_2 at equilibrium = 0.441 atm

Pressure of PCl_5 at equilibrium = 10.24 atm

The balanced equilibrium reaction is,

PCl_3(g)+Cl_2(g)\rightleftharpoons PCl_5(g)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{PCl_5})}{(p_{PCl_3})(p_{Cl_2})}

Now put all the values in this expression, we get :

K_p=\frac{(10.24)}{(0.348)(0.441)}

K_p=66.7

Therefore, the value of K_p at this temperature is 66.7

4 0
2 years ago
6) How many valence electrons does an atom of Cu possess?
agasfer [191]
The answer is c)11 because copper has 11 valence electrons
7 0
3 years ago
In a chemical equation, (aq) after one of the substances means that it is which of these? a solid formed from two ionic substanc
Vladimir79 [104]
The answer is dissolved in water, because in chemistry, (aq) is shorthand for aqueous solution.
3 0
2 years ago
Identify the oxidizing agent and the reducing agent for 4Li(s) + O_2 (g) to 2Li_2O(s).
wolverine [178]

Answer: Li is the reducing agentg and O is the oxidizing agent.

Explanation:

1) The oxidizing agent is the one that is reduced and the reducing agent is the one that is oxidized.

2) The given reaction is:

4Li(s) + O₂ (g) → 2 Li₂O(s)

3) Determine the oxidation states of each atom:

Li(s): oxidation state = 0 (since it is alone)

O₂ (g): oxidation state = 0 (since it is alone)

Li in Li₂O (s) +1

O in Li₂O -2

That because 2× (+1) - 2 = 0.

4) Determine the changes:

Li went from 0 to + 1, therefore it got oxidized and it is the reducing agent.

O went from 0 to - 2, therefore it got reduced and it is the oxidizing agent.

7 0
3 years ago
Read 2 more answers
When the [H+] in a solution is 1.7 × 10−9 M, what is the pOH ? 8.80 5.23 14 8.60
kumpel [21]
PH = -log[H+]
pH = -log[1,7×10^-9]
pH = 8,77

pH + pOH = 14
pOH = 14 - 8,77
pOH = 5,23
5 0
2 years ago
Read 2 more answers
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