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Rainbow [258]
2 years ago
9

Given:

Chemistry
1 answer:
faltersainse [42]2 years ago
5 0

Answer:

6moles of Mg

Explanation:

The reaction expression is given as:

          BO₃   +    3Mg   →    3MgO    +    B

Given:

Number of moles of B produced  = 2 moles

Unknown:

Number of moles of Mg required  = ?

Solution:

  From the balanced reaction expression:

          1 mole of B is produced from 3 moles of Mg

          2 moles of B will be produced from 2 x 3  = 6moles of Mg

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Which compounds are bases in aqueous solution according to brønsted–lowry theory?.
Fittoniya [83]

Ammonia compounds are bases in aqueous solution according to brønsted–lowry theory.

<h3>What are bases?</h3>

A base is a substance that can neutralize the acid by reacting with hydrogen ions.

Ammonia compounds are based on an aqueous solution according to brønsted–lowry theory because the water molecule donates a hydrogen ion to the ammonia, it is the Brønsted-Lowry acid, while the ammonia molecule which accepts the hydrogen ion is the Brønsted-Lowry base. Thus, ammonia acts as a base in both the Arrhenius sense and the Brønsted-Lowry sense.

Hence, ammonia compounds are based on an aqueous solution according to brønsted–lowry theory.

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2 years ago
Why are scientists now more excited about sound levitation than they had been previously?
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Explanation:

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Which factor can increase a population rate
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Earthquakes can happen at which type of plate boundaries? (Select ALL that apply)
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Read 2 more answers
Consider the decomposition of a metal oxide to its elements, where M represents a generic metal. M 3 O 4 ( s ) − ⇀ ↽ − 3 M ( s )
Citrus2011 [14]

Answer:

a) ΔGrxn = 6.7 kJ/mol

b) K = 0.066

c) PO2 = 0.16 atm

Explanation:

a) The reaction is:

M₂O₃ = 2M + 3/2O₂

The expression for Gibbs energy is:

ΔGrxn = ∑Gproducts - ∑Greactants

Where

M₂O₃ = -6.7 kJ/mol

M = 0

O₂ = 0

deltaG_{rxn} =((2*0)+(3/2*0))-(1*(-6.7))=6.7kJ/mol

b) To calculate the constant we have the following expression:

lnK=-\frac{deltaG_{rxn} }{RT}

Where

ΔGrxn = 6.7 kJ/mol = 6700 J/mol

T = 298 K

R = 8.314 J/mol K

lnK=-\frac{6700}{8.314*298} =-2.704\\K=0.066

c) The equilibrium pressure of O₂ over M is:

K=P_{O2} ^{3/2} \\P_{O2}=K^{2/3} =0.066^{2/3} =0.16atm

3 0
3 years ago
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