A+bi is a complex number
(3+2i)(a+bi)=17+7i
remember
i²=-1
so
expand and solve
a is the ral part
bi is the imaginary part
ok so
if Ac+Be=dc+fe where c=c and e=e then A=d and B=f
(3+2i)(a+bi)=17+7i
expand/distribute/FOIL
3a+2ai+3bi+2bi²=17+7i
3a+2bi+2ai+2bi=17+7i
3a-2b+2ai+2bi=17+7i
real parts are 3a-2b
imaginary is 2ai+2bi
so
3a-2b=17 and
2ai+2bi=7i
we need to solve
2nd equation, divide both sides by i
2a+2b=7
multiply by -1 and add to other equation
3a+2b=17
<u>-2a-2b=-7 +</u>
1a+0b=10
a=10
subsitue
2a+2b=7
2(10)+2b=7
20+2b=7
2b=-13
b=-13/2
the complex number is
10-(13/2)i or
10-6.5i
Answer:
8g + 152?
Step-by-step explanation:
I don't know if it's right, but 8(g+19) simplified is 8g + 152, so they would be equivalent...
Answer:
(x, y) = (1, 3)
Step-by-step explanation:
given the 2 equations
x + y = 4 → (1)
y = 3x → (2)
Substitute y = 3x into (1)
x + 3x = 4
4x = 4 ( divide both sides by 4 )
x = 1
Substitute x = 1 into (2) for corresponding value of y
y = 3 × 1 = 3
solution is (1, 3 )
807 divided by 7 = 115.2857143
