Answer:
D. All of them would have the same kinetic energy
Explanation:
The expression for the kinetic energy of the gas is:-
k is Boltzmann's constant =
T is the temperature
<u>Since, kinetic energy depends only on the temperature. Thus, at same temperature, at 300 K, all the gases which are
will posses same value of kinetic energy.</u>
<u>Answer:</u> The value of equilibrium constant is 0.997
<u>Explanation:</u>
We are given:
Percent degree of dissociation = 39 %
Degree of dissociation,
= 0.39
Concentration of
, c = 
The given chemical equation follows:

<u>Initial:</u> c -
<u>At Eqllm:</u>

So, equilibrium concentration of ![N_2O_4=c-c\alpha =[1-(1\times 0.39)]=0.61M](https://tex.z-dn.net/?f=N_2O_4%3Dc-c%5Calpha%20%3D%5B1-%281%5Ctimes%200.39%29%5D%3D0.61M)
Equilibrium concentration of ![NO_2=2c\alpha =[2\times 1\times 0.39]=0.78M](https://tex.z-dn.net/?f=NO_2%3D2c%5Calpha%20%3D%5B2%5Ctimes%201%5Ctimes%200.39%5D%3D0.78M)
The expression of
for above equation follows:
![K_{c}=\frac{[NO_2]^2}{[N_2O_4]}](https://tex.z-dn.net/?f=K_%7Bc%7D%3D%5Cfrac%7B%5BNO_2%5D%5E2%7D%7B%5BN_2O_4%5D%7D)
Putting values in above equation, we get:

Hence, the value of equilibrium constant is 0.997
I don't know what you mean by just good, but electricity wise, no. In electricity they can't conduct very well and are just so called "heat carriers." They also have higher melting and/or boiling points. I found most of this on google so if you still are lost try looking up your question. Good luck! :)
<span>One way to write a polynomial is in standard form. In order to write any polynomial in standard form, you look at the degree of each term. You then write each term in order of degree, from highest to lowest, left to write. First, look at the degrees for each term in the expression.</span> and in this way you will be able to write polynominal in standard form.
A solution is uniform throughout, so your answer is the first one.