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sergeinik [125]
3 years ago
12

PLS HELP ME I WILL GIVE BRAINLIEST TO U I JUST NEED ANSWERS ASAP

Chemistry
1 answer:
elena55 [62]3 years ago
4 0

Answer:

is this multiple choice just wondering

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What is the equilibrium constant for the following reaction? <br> 3A + 2B - &gt; 2C
san4es73 [151]
Equilibrium constant,Kc = ( [C]^2 ) ÷ ( [B]^2 × [A]^3 )
3 0
3 years ago
During a reaction 24 cubic cm of carbon dioxide was given off. After 8 minutes no more gas was produced and the reaction was com
yuradex [85]

Answer:

Explanation:

Given parameters:

Volume of CO₂ = 24cm³

time taken for the reaction to complete = 8minutes.

Unknown:

rate of reaction

Soution

The reaction rate is a measure of speed of a chemical reaction. It is often calculated using the expression below:

    Reaction rate = \frac{change in concentration of reactant/product}{time taken}

   Reaction rate = \frac{24}{8} = 3cm³/min

In this reaction, 3cm³ of carbon dioxide were produced per minute

7 0
3 years ago
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Which of the following powers the water cycle?
inessss [21]
The answer is C. Because you need the sun to start your cycle which starts with water evaporation
4 0
2 years ago
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Help answer the questions in the photo above
DanielleElmas [232]

Let the person at the Left be A and Person at the right be B

then the force by person A will be

Pulling force + Frictional Force = the force by the person

which is,

20N+11N=29N

then the force by person B will be,

25N+5N=30N

1) the net force will be 30N-29N=1N

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3) the rope will move towards the right as there is a net force of 1N towards the right.

5 0
3 years ago
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Given the following formula 2 KCIO3 -&gt; 2 KCI + 3 O2 how many moles of O2 can be produced by letting 12 moles of KCIO3 react?
poizon [28]
1st you need to find the mole ratio between KClO3 and O2.  To find that you need to take the coefficents of each of the compounds.  That gives a ratio of 2:3.

Now we find out how many each unit is:
2x = 12
x = 6

Now we multiply it by 3 to find the number of moles of O2
3(6) = 18 mol O2. 
6 0
3 years ago
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