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Reptile [31]
3 years ago
12

Which of the following best describes an atom?A)Protons and electrons grouped together in a random pattern.B) A core of electron

s and neutrons surrounded by protons. C) A core of protons and neutrons surrounded by electrons.D) I’m not sure. I need more help with this topic.
Chemistry
1 answer:
madreJ [45]3 years ago
5 0

Answer: B

Explanation:

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What is the overall equation for FeCl3(aq) + NH3(aq) + H2O(l)? the overall ionic equation? then the net ionic equation?
diamong [38]
So the question ask to calculate the over all equation for a certain element and the following are 
- over all equation -  FE(OH)3+3NH4CI
- over all ionic equation -  e(OH)3 (s) & 3 NH4+ (aq) & 3Cl- (aq) - net ionic equation -  Fe+3+3OH-+3NH$++3CI-
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3 years ago
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What steps are involved in the process that turns sediment back to rock? Select all that apply.
jeyben [28]

Answer:

compaction and cementation

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3 years ago
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A student dissolves 3.9g of aniline (C6H5NH2) in 200.mL of a solvent with a density of 1.05 g/mL . The student notices that the
Tresset [83]

Answer:

a. Molarity= M =2.1x10^{-1}M

b. Molality= m=2.0x10^{-1}m

Explanation:

Hello,

In this case, given the information about the aniline, whose molar mass is 93g/mol, one could assume the volume of the solution is just 200 mL (0.200 L) as no volume change is observed when mixing, therefore, the molarity results:

M=\frac{n_{solute}}{V_{solution}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L} =2.1x10^{-1}M

Moreover, the molality:

m=\frac{n_{solute}}{m_{solvent}} =\frac{3.9g*\frac{1mol}{93g} }{0.2L*\frac{1.05kg}{1L} } =2.0x10^{-1}m

Best regards.

7 0
3 years ago
What type of compound is fe3n2?
Kobotan [32]
I believe the type of compound fe3n2 is ionic. 
3 0
3 years ago
Determine the missing species:
Galina-37 [17]

Answer: 4. ^{0}_{-1}\textrm{e} and ^{0}_{1}\textrm{e}

Explanation:

a) The given reaction is ^{41}_{20}\textrm{Ca}+^{x}_{y}\textrm{X}\rightarrow ^{41}_{19}\textrm {K}

As the mass on both reactant and product side must be equal:

41+x=41

x=0

As the atomic number on both reactant and product side must be equal:

20+y=19

y=-1

^{41}_{20}\textrm{Ca}+^{0}_{-1}\textrm{e}\rightarrow ^{41}_{19}\textrm {K}

b) ^{15}_{8}\textrm{O}\rightarrow ^{15}_{7}\textrm{N}+^{x}_{y}\textrm{X}

Total mass on reactant side = total mass on product side

15 =15 + x

x = 0

Total atomic number on reactant side = total atomic number on product side

8 = 7 + y

y = 1

^{15}_{8}\textrm{O}\rightarrow ^{15}_{7}\textrm{N}+^{0}_{1}\textrm{e}

5 0
2 years ago
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