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nordsb [41]
4 years ago
14

1. The picture above shows salt (NaCl).

Chemistry
1 answer:
Gwar [14]4 years ago
7 0

Answer: A Chloride is attracted to the hydrogen atoms in a water molecule.

Explanation: Salt dissociates in water because Chlorine which is an anion gets attracted to the positively charged atoms of Hydrogen in water. This attraction causes Cl to bind with Hydrogen allowing Na to be left behind.

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Which substance is correctly identified as a homogeneous or heterogeneous mixture?
larisa86 [58]

Answer:

A

Explanation:

A salad with lettuce, cheese, seeds, tomatoes, broccoli, and other vegetables is an example of a heterogeneous mixture.

Milk is not mixed with anything so that is incorrect

River water is mixed in with dirt and minerals so this one is incorrect

Beach sand is incorrect because you can see colored particles.

7 0
3 years ago
How can we separate the components of a compound?
Alinara [238K]

Answer:

A mixture is a physical combination of substances thus it only requires physical processes to separate. However, a compound is chemically combined and can only be separated by chemical processes. Therefore, it is much harder to separate a compound than a mixture.

6 0
3 years ago
Is vineasel edible??????????????????????/
nevsk [136]

Answer:

no it's not edible

5 0
3 years ago
Read 2 more answers
A fish tank holds 29 gal of water. Using the density of 1.00 g/mL for water, determine the number of pounds of water in the fish
vova2212 [387]
1. Convert gallons to mL. 1 gal = 3785.4117840007 mL, multiply that by 29 and get 109776.94173602 mL.

2. Since there is one gram per every mL, there are 109776.94173602 g of water in the fish tank.

3. Convert g to pounds. 1 g = 0.0022 pounds. Multiply 109776.94173602 by 0.0022 and end up with about 241.5 pounds of water.
3 0
4 years ago
Read 2 more answers
Look at sample problem 19.10 in the 8th ed Silberberg book. Write the Ksp expression. Find the concentrations of the ions you ne
777dan777 [17]

Answer:

Explanation:

From the information given:

CaF_2 \to Ca^{2+} + 2F^-

Ksp = 3.2 \times 10^{-11}

no of moles of Ca^{2+} = 0.01 L × 0.0010 mol/L

no of moles of Ca^{2+} = 1 \times 10^{-5} \ mol

no of moles of F^- = 0.01 L × 0.00010 mol/L

no of moles of F^- = 1 \times 10^{-6}\ mol

Total volume = 0.02 L

[Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\  \\  \[[Ca^{2+}}] = 0.0005 \ mol/L

[F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}

[F^{-}] = 5 \times 10^{-5}  \ mol/L

Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}

Since Q<ksp, then there will no be any precipitation of CaF2

3 0
3 years ago
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