Answer:
50 g of K₂CO₃ are needed
Explanation:
How many grams of K₂CO₃ are needed to make 500 g of a 10% m/m solution?
We analyse data:
500 g is the mass of the solution we want
10% m/m is a sort of concentration, in this case means that 10 g of solute (K₂CO₃) are contained in 100 g of solution
Therefore we can solve this, by a rule of three:
In 100 g of solution we have 10 g of K₂CO₃
In 500 g of solution we may have, (500 . 10) / 100 = 50 g of K₂CO₃
Answer:
Molarity = 12 M
Explanation:
Given data:
Molarity of solution = ?
Number of moles of NaCl = 3.0 mol
Volume of solution = 250 mL (250/1000 = 0.25 L)
Solution:
Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.
Formula:
Molarity = number of moles of solute / L of solution
Molarity = 3.0 mol / 0.25 L
Molarity = 12 M
Answer:
Increases in temperature tend to decrease density since volume will generally increase. There are exceptions however, such as water's density increasing between 0°C and 4°C. Below is a table of units in which density is commonly expressed, as well as the densities of some common materials.
Explanation:
On the earth there is the top layer dirt then loam comes next
