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slega [8]
3 years ago
8

Describe three types of POTENTIAL ENERGY

Chemistry
1 answer:
Arada [10]3 years ago
8 0

There are three different forms of potential energy. The rock hanging above the ground has a form of stored energy called gravitational potential energy. This form of energy is due to the downward pull of Earth's gravity. ... When you stretch a rubber band, the elastic potential energy of the rubber band increases.

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Landslides are an example of
ivanzaharov [21]

Answer:

b. erosion.

I believe that this is the best answer

8 0
3 years ago
Read 2 more answers
A hypothetical metal crystallizes with the face-centered cubic unit cell. The radius of the metal atom is 234 picometers and its
AleksAgata [21]

Answer:

\delta=101.13 g/cm^3

Explanation:

As can be seen in the Figure in a face-centered cubic unit cell you have:

  • Six halves of atoms
  • Eight 1/8 of atom (1 in each corner)

In total:

n_{atom}=6*0.5+8*\frac{1}{8}=4 atoms

Now, each side of the cell is 234 picometers (2.34e-8 cm) long

V_{cell}=L^3=(2.34e^{-8} cm)^3

V_{cell}=1.28*10^{-23}cm^3

Atoms per cm3:

n=\frac{4 atoms}{1.28*10^{-23}cm^3}

n=3.12*10^{23} atoms/cm^3

Expressing in mass:

\delta=3.12*10^{23} atoms/cm^3* \frac{1 mol}{6.022*10^{23}}*195.08 g/mol

\delta=101.13 g/cm^3

6 0
4 years ago
Taking a test please help. Thank you.
Komok [63]
It’s the 3rd one obviously bro
3 0
3 years ago
The standard enthalpy change for the following reaction is 232 kJ at 298 K. 2 H2CO(g) 2 C(s,graphite) + 2 H2(g) + O2(g) ΔH° = 23
Georgia [21]

Answer:  The standard enthalpy change for this reaction is -116 kJ

Explanation:

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given chemical reaction is,

2H_2CO(g)\rightarrow 2C(s, graphite)+2H_2(g)+O_2(g)

\Delta H^0=232KJ

Now we have to determine the value of \Delta H for the following reaction i.e,

)C(s, graphite)+H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2CO(g) \Delta H^0'=?

According to the Hess’s law, if we reverse the reaction then the \Delta H will change its sign and if we half the reaction, then the

So, the value \Delta H^0' for the reaction will be:

\Delta H^0'=\frac{(-232kJ/mole)}{2}=-116kJ

Hence, the standard enthalpy change for this reaction is -116 kJ

7 0
4 years ago
Down there (pls hurryy!!)
ivanzaharov [21]

Answer:

E

Explanation:

Hope this helps!

5 0
3 years ago
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