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LuckyWell [14K]
3 years ago
5

Any substance composed of two or more elements that are chemically combined in a fixed proportion is

Chemistry
1 answer:
laila [671]3 years ago
5 0
It is a compound……….
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Given: h2o(aq) + h2o(l) h3o+(aq) + oh–(aq) δh°rxn > 0 when the temperature of a sample of pure water is raised above 25°c,
sesenic [268]
When Δ H > 0 that means this is an endothermic reaction, and we can assume heat as one of the reactants. SO when the temperature increases so the reaction will move rightward to decrease the reactants and increase the products and as the products increase it will make the Kw increase also as
 Kw = [Products] /[reactants].

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In an addition reaction to an alkene the pi bond plays the role of
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Nucleophile electrophile
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Imagine you have a 1.0 mL water sample containing 0.10 M hydrochloric acid, HCl. You want to get it to a safe pH of 6. How much
AVprozaik [17]

Answer:

See explanation below

Explanation:

In this case, HCl is a strong acid, therefore, it dissociates completely in solution.

To know the quantity of water we need to add, we first need to know the concentration of the acid with pH = 6:

[H⁺] = antlog(-pH)

[H⁺] = antlog(-6) = 1x10⁻⁶ M

This means that the concentration is being diluted.

Now, even if we add great quantities of water, and the concentration and volume change, there is one time that do not change despite the quantity of water added; this is the moles. So, all we have to do, is calculate the moles of the acid in the 1 mL of water, and then, the volume of the acid when it's dilluted:

moles HCl = 0.1 * (1/1000) = 1x10⁻⁴ moles

Now that we have the moles, we can calculate the volume which the acid with the lowest concentration has:

V = mol/M

V = 1x10⁻⁴ / 1x10⁻⁶

V = 100 L

This means that we need to add 99.999 mL of water

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3 years ago
When a drawing of a circle made in the center of a piece of paper with a black marker gets wet, the marker bleeds, and as the wa
Ahat [919]

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Chromatography

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A 3.5 M KNO3 solution contains 3.5 miles of KNO3 dissolved in A) 1.0 liter of solution B) 1.0 liter of solvent C) 3.5 liters of
Vladimir [108]
N=3.5 mol
c=3.5 mol/L

n=cv

v=n/c

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A) 1.0 liter of solution
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