Answer:
![H^++NH_3\rightleftharpoons NH_4^+](https://tex.z-dn.net/?f=H%5E%2B%2BNH_3%5Crightleftharpoons%20NH_4%5E%2B)
Explanation:
Hello there!
In this case, since the buffer is not given, we assume it is based off ammonia, it means the ammonia-ammonium buffer, whereas the ammonia is the weak base and the ammonium ion stands for the conjugate acid. In such a way, when adding HI to the solution, the base of the buffer, NH3, reacts with the former to promote the following chemical reaction:
![H^++NH_3\rightleftharpoons NH_4^+](https://tex.z-dn.net/?f=H%5E%2B%2BNH_3%5Crightleftharpoons%20NH_4%5E%2B)
Because the HI is totally ionized in solution so the iodide ion becomes an spectator one.
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Answer:
Atoms
Explanation:
Energy, potential energy, is stored in the covalent bonds holding atoms together in the form of molecules. This is often called chemical energy.
Answer:
-100 kJ
Explanation:
We can solve this problem by applying the first law of thermodynamics, which states that:
![\Delta U = Q-W](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20Q-W)
where:
is the change in internal energy of a system
Q is the heat absorbed/released by the system (it is positive if absorbed by the system, negative if released by the system)
W is the work done by the system (it is positive if done by the system, negative if done on the system)
For the system in this problem we have:
W = +147 kJ is the work done by the system
Q = +47 kJ is the heat absorbed by the system
So , its change in internal energy is:
![\Delta U = +47 - (+147) =-100 kJ](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20%2B47%20-%20%28%2B147%29%20%3D-100%20kJ)
Answer:
E. 16.6 mol HCl
Explanation:
The equation for the reaction is;
Zn + 2 HCl --> ZnCl2 + H2
From the reaction 2 moles of HCl produces 1 mole of ZnCl2
Therefore; 8.3 moles of ZnCl2 will be produced by;
= 8.3 moles ×2
= 16.6 Moles of HCl
Therefore; E. 16.6 mol HCl
<u>Answer:</u> The volume of given amount of ethanol at this temperature is 159.44 mL
<u>Explanation:</u>
Specific gravity is given by the formula:
![\text{Specific gravity}=\frac{\text{Density of a substance}}{\text{Density of water}}](https://tex.z-dn.net/?f=%5Ctext%7BSpecific%20gravity%7D%3D%5Cfrac%7B%5Ctext%7BDensity%20of%20a%20substance%7D%7D%7B%5Ctext%7BDensity%20of%20water%7D%7D)
We are given:
Density of water = 0.997 g/mL
Specific gravity of ethanol = 0.787
Putting values in above equation, we get:
![0.787=\frac{\text{Density of a substance}}{0.997g/mL}\\\\\text{Density of a substance}=(0.787\times 0.997g/mL)=0.784g/mL](https://tex.z-dn.net/?f=0.787%3D%5Cfrac%7B%5Ctext%7BDensity%20of%20a%20substance%7D%7D%7B0.997g%2FmL%7D%5C%5C%5C%5C%5Ctext%7BDensity%20of%20a%20substance%7D%3D%280.787%5Ctimes%200.997g%2FmL%29%3D0.784g%2FmL)
Density is defined as the ratio of mass and volume of a substance.
......(1)
Given values:
Mass of ethanol = 125 g
Density of ethanol = 0.784 g/mL
Putting values in equation 1, we get:
![\text{Volume of ethanol}=\frac{125g}{0.784g/mL}=159.44mL](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20ethanol%7D%3D%5Cfrac%7B125g%7D%7B0.784g%2FmL%7D%3D159.44mL)
Hence, the volume of given amount of ethanol at this temperature is 159.44 mL