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lisabon 2012 [21]
3 years ago
7

Which property is demonstrated below? n•1=n

Mathematics
1 answer:
Vinvika [58]3 years ago
3 0

Answer:

Step-by-step explanation:

That'd be the Identity Property of Multiplication.

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Translate into an algebraic expressions: b is decreased by 40% and decreased again by 40% . What is the result ?
Vikki [24]

Answer:

b-4/5b

Step-by-step explanation:

b is decreased by 80%

dat is 80/100×b

= b-80/100b

b-4/5b

5 0
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4x.5x³.2x⁵ find the product​
Marat540 [252]
The answer is b and i know that cause just david’s
8 0
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What is the mode of the following set of numbers? 121, 347, 45, 21, 300, 614, 312, 333, 421 no mode 279.3 312 21
Lorico [155]
There is no mode. Hope this helps
5 0
3 years ago
Read 2 more answers
A random sample of n = 40 observations from a quantitative population produced a mean x = 2.2 and a standard deviation s = 0.29.
zmey [24]

Answer:

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

Step-by-step explanation:

Data given and notation  

\bar X=2.2 represent the sample mean

s=0.29 represent the sample standard deviation

n=40 sample size  

\mu_o =2.1 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean is higher than 2,1, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.1  

Alternative hypothesis:\mu > 2.1  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{2.2-2.1}{\frac{0.29}{\sqrt{40}}}=2.18    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=40-1=39  

Since is a one side test the p value would be:  

p_v =P(t_{(39)}>2.18)=0.0177  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and then the population mes seems to be higher than 2.1 at 5% of significance

7 0
3 years ago
A student deposits the same amount of money into her bank account each week. At the end of the second week she has $30 in her ac
Nonamiya [84]
The student will have $135 in her bank account at the end of the ninth week. You can fine this out by finding out the amount she deposits a week and to do this you would take the $30 and divide it by 2 because she had $30 at the end of the second week. 
30/2=15
So you see that the student deposits $15 each week, so to find out how much money she will have in 9 weeks you will multiply her $15 by 9.
15x9=135
So the student will have $135 at the end of the ninth week. 
6 0
3 years ago
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