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3 years ago

9

Betty the cow gave 375 litres less than twice the amount from Bessie the cow. Together, Betty and Bessie produced 1464 litres of

milk. How many litres did each cow give?

1 answer:

Mamont248 [21]3 years ago

5 0

If u like use subtract and addition to it it would be 1089

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Which expression is equivalent to V-80?<br> -4V5<br> -4V5i<br> 4V5i<br> 4V5

sattari [20]

Answer:

-4v5

Step-by-step explanation:

just a guess

6 0

3 years ago

Help find the value of x pls. No links! Y

Citrus2011 [14]

=>7x+9=9x+5

=>7x+9-9=9x+5-9

=>7x=9x-4

=>7x-9x=9x-4-9x

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=>7x+9=7×2+9=23

=>9x+5=9×2+5=23

4 0

3 years ago

Simplify. Assume all variables are non-zero. HELP ASAP!

Alexandra [31]

Answer:

D

Step-by-step explanation:

((p^4*q)/p^8)^2.

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4 0

4 years ago

A box designer has been charged with the task of determining the surface area of various open boxes (no lid) that can be constru

Viktor [21]

Answer:

1) $S = 2\cdot w\cdot l - 8\cdot x^{2}$ , 2) The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$ , 3) $S = 176\,in^{2}$ , 4) $x \approx 4.528\,in$ , 5) $S = 164.830\,in^{2}$

Step-by-step explanation:

1) The function of the box is:

$S = 2\cdot (w - 2\cdot x)\cdot x + 2\cdot (l-2\cdot x)\cdot x +(w-2\cdot x)\cdot (l-2\cdot x)$

$S = 2\cdot w\cdot x - 4\cdot x^{2} + 2\cdot l\cdot x - 4\cdot x^{2} + w\cdot l -2\cdot (l + w)\cdot x + l\cdot w$

$S = 2\cdot (w+l)\cdot x - 8\cdpt x^{2} + 2\cdot w \cdot l - 2\cdot (l+w)\cdot x$

$S = 2\cdot w\cdot l - 8\cdot x^{2}$

2) The maximum cutout is:

$2\cdot w \cdot l - 8\cdot x^{2} = 0$

$w\cdot l - 4\cdot x^{2} = 0$

$4\cdot x^{2} = w\cdot l$

$x = \frac{\sqrt{w\cdot l}}{2}$

The domain of S is $0 \leq x \leq \frac{\sqrt{w\cdot l}}{2}$ . The range of S is $0 \leq S \leq 2\cdot w \cdot l$

3) The surface area when a 1'' x 1'' square is cut out is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1\,in)^{2}$

$S = 176\,in^{2}$

4) The size is found by solving the following second-order polynomial:

$20\,in^{2} = 2 \cdot (8\,in)\cdot (11.5\,in)-8\cdot x^{2}$

$20\,in^{2} = 184\,in^{2} - 8\cdot x^{2}$

$8\cdot x^{2} - 164\,in^{2} = 0$

$x \approx 4.528\,in$

5) The equation of the box volume is:

$V = (w-2\cdot x)\cdot (l-2\cdot x) \cdot x$

$V = [w\cdot l -2\cdot (w+l)\cdot x + 4\cdot x^{2}]\cdot x$

$V = w\cdot l \cdot x - 2\cdot (w+l)\cdot x^{2} + 4\cdot x^{3}$

$V = (8\,in)\cdot (11.5\,in)\cdot x - 2\cdot (19.5\,in)\cdot x^{2} + 4\cdot x^{3}$

$V = (92\,in^{2})\cdot x - (39\,in)\cdot x^{2} + 4\cdot x^{3}$

The first derivative of the function is:

$V' = 92\,in^{2} - (78\,in)\cdot x + 12\cdot x^{2}$

The critical points are determined by equalizing the derivative to zero:

$12\cdot x^{2}-(78\,in)\cdot x + 92\,in^{2} = 0$

$x_{1} \approx 4.952\,in$

$x_{2}\approx 1.548\,in$

The second derivative is found afterwards:

$V'' = 24\cdot x - 78\,in$

After evaluating each critical point, it follows that $x_{1}$ is an absolute minimum and $x_{2}$ is an absolute maximum. Hence, the value of the cutoff so that volume is maximized is:

$x \approx 1.548\,in$

The surface area of the box is:

$S = 2\cdot (8\,in)\cdot (11.5\,in)-8\cdot (1.548\,in)^{2}$

$S = 164.830\,in^{2}$

4 0

3 years ago

Sheldon wants to buy a laptop that costs $ 450 from an electronics store . He has two coupons to choose from coupon A which give

Gekata [30.6K]

Answer:

Coupon B

Step-by-step explanation:

Given

$Price = \$450$

$Coupon\ A = \$80$

$Coupon\ B = 20.5\%$

Required

Which coupon is better

From the question, we have:

$Coupon\ A = \$80$

$Coupon\ B = 20.5\%$

Coupon B means that:

$Coupon\ B = 20.5\% * \$450$

$Coupon\ B = 0.205 * \$450$

$Coupon\ B = \$92.25$

By comparison:

Coupon B gives him a better buy because: $\$92.25 > \$80$

7 0

3 years ago