One of the triangles (that on the left, top) has 2 equal sides, and thus is isosceles. The angle immediately adjacent to and to the right of 110 degrees is 180-110 degrees, or 70 degrees, which means that angle 1 is also 70 degrees. The remaining angle is 180 degrees less 2(70 degrees), or 40 degrees; thus, angle 2, immediately adjacent to and to the right of this 40 degree angle, is 180-40, or 140 degrees. The triangle to the right and below the horiz. line has angle 40 degrees (using the principle of vertical angles); thus, angle 3 is 180-(40+90) degrees, or 50 degrees.
Answer:
![SU=3.5\ units](https://tex.z-dn.net/?f=SU%3D3.5%5C%20units)
Step-by-step explanation:
step 1
In the isosceles right triangle PQT
PQ=PT ----> because is an isosceles triangle
Applying the Pythagoras Theorem
we have
![PQ=PT =\sqrt{2}\ units](https://tex.z-dn.net/?f=PQ%3DPT%20%3D%5Csqrt%7B2%7D%5C%20units)
![QT^{2}=PQ^{2} +PT^{2}](https://tex.z-dn.net/?f=QT%5E%7B2%7D%3DPQ%5E%7B2%7D%20%2BPT%5E%7B2%7D)
substitute the values
![QT^{2}=\sqrt{2}^{2} +\sqrt{2}^{2}](https://tex.z-dn.net/?f=QT%5E%7B2%7D%3D%5Csqrt%7B2%7D%5E%7B2%7D%20%2B%5Csqrt%7B2%7D%5E%7B2%7D)
![QT^{2}=4](https://tex.z-dn.net/?f=QT%5E%7B2%7D%3D4)
![QT=2\ units](https://tex.z-dn.net/?f=QT%3D2%5C%20units)
step 2
In the square QRST
![RS=QT=2\ units](https://tex.z-dn.net/?f=RS%3DQT%3D2%5C%20units)
step 3
In the right triangle RSU
Applying the Pythagoras Theorem
![RU^{2}=RS^{2} +SU^{2}](https://tex.z-dn.net/?f=RU%5E%7B2%7D%3DRS%5E%7B2%7D%20%2BSU%5E%7B2%7D)
we have
![RU=4\ units](https://tex.z-dn.net/?f=RU%3D4%5C%20units)
![RS=2\ units](https://tex.z-dn.net/?f=RS%3D2%5C%20units)
substitute the values and solve for SU
![4^{2}=2^{2} +SU^{2}](https://tex.z-dn.net/?f=4%5E%7B2%7D%3D2%5E%7B2%7D%20%2BSU%5E%7B2%7D)
![SU^{2}=4^{2}-2^{2}](https://tex.z-dn.net/?f=SU%5E%7B2%7D%3D4%5E%7B2%7D-2%5E%7B2%7D)
![SU^{2}=12](https://tex.z-dn.net/?f=SU%5E%7B2%7D%3D12)
![SU=2\sqrt{3}\ units](https://tex.z-dn.net/?f=SU%3D2%5Csqrt%7B3%7D%5C%20units)
![SU=3.5\ units](https://tex.z-dn.net/?f=SU%3D3.5%5C%20units)
Answer:
![C.\ Perimeter = 48 * 18](https://tex.z-dn.net/?f=C.%5C%20Perimeter%20%3D%2048%20%2A%2018)
Step-by-step explanation:
Given
See attachment for her sketch
Required
Which equation do not represent the perimeter
From the attached sketch:
--- Length
--- Width
Perimeter (P) is calculated as:
![P = 2 * (L + W)](https://tex.z-dn.net/?f=P%20%3D%202%20%2A%20%28L%20%2B%20W%29)
This gives:
---- This represents (A)
Open bracket
---- This represents (B)
In algebra:
means ![a+ a](https://tex.z-dn.net/?f=a%2B%20a)
So, the expression becomes
--- This represents (D)
<em>This implies that (C) does not represent the perimeter</em>
Sure i can help where is it?
3 is the common difference