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Gre4nikov [31]
3 years ago
15

True or false: Pollen contains the male gamete of the plant

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
6 0
False pollen<span> is transported to nearby </span>plants<span> by raindrops. ... embryo sac of angiosperms </span>consists of<span> eight diploid cells and one haploid egg cell</span>
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It is considered a DUI if the driver’s Blood Alcohol Content level is at or above .08.
Tom [10]
I would put yes as in California the dui is .08 or above
5 0
3 years ago
1) The heat of combustion for the gases hydrogen, methane and ethane are −285.8, −890.4 and −1559.9 kJ/mol respectively at 298K.
Morgarella [4.7K]

Answer:

The enthalpy of the reaction is 64.9 kJ/mol.

Explanation:

H_2 + \frac{1}{2}O_2\rightarrow H_2O,\Delta H_1 =-285.8 kJ..[1]

CH_4 + 2O_2\rightarrow CO_2 + 2H_2O,\Delta H_2 =-890.4 kJ..[2]

C_2H_6 + \frac{7}{2}O_2\rightarrow 2CO_2 + 3H_2O,\Delta H_3= -1559.9 kJ..[3]

2CH_4(g)\rightarrow C_2H_6(g) + H_2(g),\Delta H_4=?..[4]

2 × [2] - [1]- [3] = [4]  (Using Hess's law)

\Delta H_4=2\times \Delta H_2 -\Delta H_1 -\Delta H_3

\Delta H_4=2\times (-890.4 kJ)-(-285.8 kJ) -(-1559.9 kJ)

\Delta H_4=64.9 kJ/mol

The enthalpy of the reaction is 64.9 kJ/mol.

3 0
3 years ago
One orbit of the earth around the sun equals _____________ miles.
garri49 [273]

Answer:

it's about 580millon, but the closest you have is 595 million, so pick that one

4 0
3 years ago
Read 2 more answers
How many grams of O2 are needed to react with 18.2 g of NH3?
erastova [34]

Answer:

44 g oxygen are needed.

Explanation:

Given data:

Mass of oxygen needed = ?

Mass of ammonia = 18.2 g

Solution:

Chemical equation:

4NH₃ + 5O₂   →  4NO + 6H₂O

Now we will calculate the number of moles of ammonia:

Number of moles = mass/molar mass

Number of moles = 18.2 g/ 17 g/mol

Number of moles = 1.1 mol

Now we will compare the moles of ammonia with oxygen from balance chemical equation.

                        NH₃              :                O₂

                          4                 :                 5

                          1.1                :              5/4×1.1 = 1.375 mol

Mass of oxygen needed:

Mass = number of moles × molar mass

Mass = 1.375 mol × 32 g/mol

Mass = 44 g

4 0
3 years ago
Ethylene glycol (antifreeze) has a density of 1.11 g/cm^3. What is the volume in liters of 3.46 kg of ethylene glycol?
xenn [34]
3.11 i'm not sure about measurements  maybe like 3.11kg/cm^3
7 0
3 years ago
Read 2 more answers
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