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Alina [70]
3 years ago
5

I need help solving this problem !!

Chemistry
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

A:Boyle's Law or B:Charles's Law

 

Explanation:

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if the percent by volume is 2% and the volume of solution is 250 mL what is the volume of solute and solution
Liula [17]

Answer:

Solute = 5 mL; solution = 250 mL  

Explanation:

The formula for percent by volume is

\text{Percent by volume} = \dfrac{\text{Volume of solute}}{\text{Volume of solution}}\times 100 \, \%

If you have 250 mL of a solution that is 2 % v/v,

\begin{array}{rcl}2 \, \% & = & \dfrac{\text{Volume of solute}}{\text{250 mL}}\times 100 \, \%\\\\2 \times \text{ 250 mL} & = & \text{Volume of solute} \times 100\\\text{Volume of solute} & = & \dfrac{2 \times 250\text{ mL}}{100}\\\\ & = & \textbf{5 mL}\\\end{array}

If there is no change of volume on mixing,

Volume of solution = 250 mL

 -Volume of solute = <u>     </u><u>5</u><u>      </u>

 Volume of solvent = 245 mL

5 0
3 years ago
Which two elements make up the greatest percentages by mass in Earth’s crust?
yuradex [85]
<h2><u>Answer</u> :</h2>

The most appropriate option is :

\hookrightarrow \bf2. \:  \mathrm{ \underline{oxygen \:  \: and \:  \: silicon}}

Since, they are the most abundant elements found in Earth's Crust.

  • Oxygen (46%)

  • Silicon (28%)

\circ  { \underline{ \boxed{ \sf{ \color{green}{ \mathrm{hope \:  \: it \:  \: helps \:  \: you .....}}}}}}∘

4 0
2 years ago
10 POINTS
Snowcat [4.5K]
E=hc/λ =6.626×10^-34×3 ×10^8 / 3×10^7 × 10^-9 = 6.626×10 ^-24J.
7 0
3 years ago
How many sig fig does 0.000925g have
Assoli18 [71]

Answer:

Sig fig 3 decimal 6

Explanation:

Hii

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8 0
3 years ago
To measure the speed of a car, we use miles per hour (miles/hour or mi/h or mph). To measure the rate of a reaction we use molar
arsen [322]

Answer:

Part A: 47.8 mi/h

Part B: 0.072 M/s

Part C: 0.144 M/s

Explanation:

Part A

The average speed or velocity (V) is the variation of the space divided by the variation of the time:

V = (241 - 2)/(8 -3)

V = 47.8 mi/h

Part B

As Part A, the average rate (r) of formation of I2 is the variation of the concentration divided by the variation of time:

r = (1.83 - 1.11)/(15 - 5)

r = 0.072 M/s

Part C

The rates of the substances are proportional of their number of moles (n) which are their coefficient, so:

rI2/nI2 = rHCl/nHCl

0.072/1 = rHCl/2

rHCl = 2*0.072

rHCl = 0.144 M/s

7 0
2 years ago
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