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Kryger [21]
3 years ago
6

A satellite with a mass of 2,000 ㎏ is inserted into an orbit that is twice the Earth' s radius. W hat is the force of gravity on

the satellite? The radius of the Earth is 6380 km, and the mass of the Earth is 5.98 X 1024 kg a. 2,000 N h. 4,900 N 19,600 N d 24,500 N e 36.200 N l Space Station which orbits Earth, astronauts experience apparenst
Physics
1 answer:
dolphi86 [110]3 years ago
4 0

Answer:

option (b) 4900 N

Explanation:

m = 2000 kg, R = 6380 km = 6380 x 10^3 m, Me = 5.98 x 10^24 kg, h = R

F = G Me x m / (R + h)^2

F = G Me x m / 2R^2

F = 6.67 x 10^-11 x 5.98 x 10^24 x 2000 / (2 x 6380 x 10^3)^2

F = 4900 N

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Answer:

C

Explanation:

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2 years ago
A ____ exerted by an object on another is a force​
Hitman42 [59]

Answer:

A gravitational force exerted by an object on another is a force.

Explanation:

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Angelina_Jolie [31]
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5 0
2 years ago
A cylindrical rod of length L is connected across a fixed potential difference, creating a current I through the rod. What would
Inessa05 [86]

Answer:

The value of current through the rod becomes half

i' = \frac{i}{2}

Explanation:

As per Ohm's law we know that the current through a resistor is given as

i = \frac{V}{R}

here we know that

R = \rho \frac{L}{A}

here we know that the length of the cylinder is L and area is A so the value of current through the rod is given as

i = \frac{V A}{\rho L}

now we have change the length of the conductor to twice of initial value and rest all parameters will remain the same

so we will have

i' = \frac{VA}{\rho (2L)}

now from above two equations we have

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3 0
3 years ago
At the Equator near Earth’s surface, the magnetic field is approximately 82.2 µT northward and the electric field is about 143 N
IrinaK [193]

Answer:

Magnitude of gravitational force of the electron= 3.74×10^12N

Explanation:

Felectron= Fgravitational

Therefore:

Felectron/Fgravitational = kq^2/r^2 ×(r^2/Gm^2)

= kq^2/Gm^2

Where G= gravitational constant

m = mass of electron=9.1×10^-31

K= 8.9x10^9

q= 1.6×10^-19

Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)

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= 3.74×10^12N

7 0
3 years ago
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