Answer:
C
Explanation:
elements are classified as covalent, ionic, metallic
Answer:
A gravitational force exerted by an object on another is a force.
Explanation:
hope it helps
Answer:
The value of current through the rod becomes half

Explanation:
As per Ohm's law we know that the current through a resistor is given as

here we know that

here we know that the length of the cylinder is L and area is A so the value of current through the rod is given as

now we have change the length of the conductor to twice of initial value and rest all parameters will remain the same
so we will have

now from above two equations we have

so new current will become

Answer:
Magnitude of gravitational force of the electron= 3.74×10^12N
Explanation:
Felectron= Fgravitational
Therefore:
Felectron/Fgravitational = kq^2/r^2 ×(r^2/Gm^2)
= kq^2/Gm^2
Where G= gravitational constant
m = mass of electron=9.1×10^-31
K= 8.9x10^9
q= 1.6×10^-19
Magnitude of gravitational force= (8.9×10^9)×(1.6×10^-19)^2/(6.7×10^-11)×(9.1×10^-31)
=( 2.2784×10^-28) / ( 6.097×10^-41)
= 3.74×10^12N