Question

An incredible amount of electrical energy passes down the funnel of a large tornado every second. Measurements taken in Oklahoma at a distance of 9.00 km from a large tornado showed an almost constant magnetic field of 1.50 · 10 -8 T associated with the tornado. What was the average current going down the funnel? (µo = 4π · 10 -7 T·m/A)

Answer 1

Answer:

675 A

Explanation:

B = 1.5 x 10^-8 T

r = 9 km = 9000 m

Let the current be i

The formula for the magnetic filed due to a very long straight conductor is given by

$B =\frac{\mu_{0}}{4\pi }\times \frac{2i}{r}$

$1.5\times 10^{-8} =10^{-7}\times \frac{2i}{9000}$

i = 675 A