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iren2701 [21]
3 years ago
11

A ship, carrying freshwater to a desert island in the caribbean, has a horizontal cross-sectional area of 2800 m2 at the waterli

ne. when unloaded, the ship rises 9.50 m higher in the sea. how much water was delivered?
Physics
1 answer:
Alex17521 [72]3 years ago
3 0
<span>Due that we already know the horizontal cross-sectional area of the ship, which is 2800 m2 and we are going to understand that value keeps constant for the whole 9.5 of height of the ship from the waterline till the new waterline after unloading, then we just need to calculate the volume as follows: V = A * H , where V is volume, A is area and H is height V= 2,800 * 9.5 = 26,600 m3 So this volum of 26,600 cubic meters is the volum of freshwater delivered in the island.</span>
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PLZ HELP ON #22-26!!!! <br><br>Please explain why and how you got your answer.
AleksAgata [21]
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a = -3.1 m/s^2

23. Find the time (t) to reach 33 m/s at 3 m/s^2
33-0/t = 3 
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t = 11 sec to reach 33 m/s^2
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24. The sprinter starts from rest. The average acceleration is found from: 
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S = v^2 - u^2/2a = (0ms^-1)^2-(21.0ms^-1)^2/2*-3.50ms^-2 = 63.0m 

26. Assuming a constant deceleration of 7.00 m/s^2
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displacement, s - 92m 
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I hope this helps!! 

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Therefore, when simple covalent substance melts,only the intermolecular forces are broken leaving only the covalent bond in the substance.

(2) poor conductivity: for a substance to conduct electricity,it must have charged particles which are free to move to and fro.

But in the simple covalent substance,there are no charged particles that can be separated due to the covalent bond present in simple covalent substance.

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