Explanation:
Let
are the number of turns in primary and secondary coil of the transformer such that,

A resistor R connected to the secondary dissipates a power 
For a transformer, 

...............(1)
The power dissipated through the secondary coil is :


.............(2)
Let
are the new number of turns in primary and secondary coil of the transformer such that,

New voltage is :

...............(3)
So, new power dissipated is 





So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.
Answer:
120 N
Explanation:
F=ma therefore 60kg times 2m/s^2 is 120 N
Answer:
Two times as much
Explanation:
The equation for gravitational force is: Fg = GMm/r^2 with G being the universal gravitational constant.
So to make things easier we'll set r equal to 1 since it's a constant as well as G.
Then we're left with Fg=Mm with M being the mass of the sun and m being the mass of the earth.
So if m is constant and supposedly equals 1 then Fg=M so Fg is proportional to M therefore if M doubles then Fg doubles.
Answer:
16 J
Explanation:
It is given that,
Work done, W = 2 J
A spring is stretched by 2.0 cm from its equilibrium length
We need to find how much more work will be required to stretch it an additional 4.0 cm.
Let k is the spring constant of the spring. When W = 2J, and x = 2 cm, then energy required to stretch the spring is :

The energy required to stretch the spring from 2 cm to additional 4 cm i.e. 2+4= 6 cm.

So, the required work done is 16 J.