How far apart (in mm) must two point charges of 90.0 nC (typical of static electricity) be to have a force of 3.80 N between the
1 answer:
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Answer:
Explanation:
The speed increased from 2.0 * 10^7 m/s to 4.0 * 10^7 m/s over a 1.2 cm distance.
Let us find the acceleration:
Electric force is given as the product of charge and electric field strength:
F = qE
where q = electric charge
E = Electric field strength
Force is generally given as:
F = ma
where m = mass
a = acceleration
Equating both:
ma = qE
E = ma / q
For an electron:
m = 9.11 × 10^{-31} kg
q = 1.602 × 10^{-19} C
Therefore, the electric field strength of the electron is:
Answer:
4.5 m/s
Explanation:
The rock must barely clear the shelf below, this means that the horizontal distance covered must be
while the vertical distance covered must be
The rock is thrown horizontally with velocity , so we can rewrite the horizontal distance as
where t is the time of flight. Re-arranging the equation,
(1)
The vertical distance covered instead is
where we omit the term since the initial vertical velocity is zero. From this equation,
(2)
Equating (1) and (2), we can solve the equation to find :
Answer:
Option A. 4 m
Explanation:
Please see attached photo for diagram.
In the attached photo, X is the distance from the centre to which the student on the right must sit in order to balance the seesaw.
Clockwise moment = X × 45
Anticlock wise moment = 3 × 60
Clockwise moment = Anticlock wise moment
X × 45 = 3 × 60
X × 45 = 180
Divide both side by 45
X = 180 / 45
X = 4 m
Thus, the student must sit at 4 m from the centre.
