<span>The probability, or expectation value for X in a block, equals the number of occurrences of X in all the blocks divided by the total number of blocks
</span>
well E(X)=µ
and
Var(X)=E[(X-µ)^2]
Using PEMDAS
P = 1x1+9x(0.01)+1x(0.001)
E = no change
M = 1+0.09+0.001
D = no change
A = 1.091
S = no change
final answer is 1.091
1 in 14 or 1/14
this is the formula I used to calculate:
Probability = Favorable cases / Possible cases
Answer:
im pretty sure the answer would be C'D' and CD would be equal in length!
Step-by-step explanation:
because you are only reflecting it across the y-axis, no changes will be made to the line itself, only the location of the line :)
