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Rudiy27
3 years ago
8

What is the value of (-0.4)^3

Mathematics
2 answers:
Fittoniya [83]3 years ago
6 0

Answer:

-(2/5)^3 or -8/125 or -0.064

Step-by-step explanation:

convert the decimal into a fraction

then use your calculator to find the exact answer

Pie3 years ago
4 0

Answer:

simplify 2/5

equation at the end of step 1:

(0-2/5)^3

step 2:

2.1

Negative number raised to an odd power is negative  

To show this we begin with (-7)5 ,a negative number raised to an odd exponent:

(-7)5 can be written as (-7)•(-7)•(-7)•(-7)•(-7)

Now, using the rule that says minus times minus is plus, (-7)5 can be written as (49)•(49)•(-7) which is a negative number.  

We showed that (-7)5 is a negative number  

Using the same arguments as above, replacing (-7) by any negative number, and replacing the exponent 5 by any odd exponent, we proved which had to be proved

final result:-2^3/5^3=-0.06400

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A batch of 40 semiconductor chips is inspected by choosing a sample of 5 chips. Assume 10 of the chips do not conform to custome
butalik [34]

Answer:

a) 658008 samples

b) 274050 samples

c) 515502 samples

Step-by-step explanation:

a) How many ways sample of 5 each can be selected from 40 is just a combination problem since the order of selection isn't important.

So, the number of samples = ⁴⁰C₅ = 658008 samples

b) How many samples of 5 contain exactly one nonconforming chip?

There are 10 nonconforming chips in the batch, and 1 nonconforming chip for the sample of 5 be picked from ten in the following number of ways

¹⁰C₁ = 10 ways

then the remaining 4 conforming chips in a sample of 5 can be picked from the remaining 30 total conforming chips in the following number of ways

³⁰C₄ = 27405 ways

So, total number of samples containing exactly 1 nonconforming chip in a sample of 5 = 10 × 27405 = 274050 samples

c) How many samples of 5 contain at least one nonconforming chip?

The number of samples of 5 that contain at least one nonconforming chip = (Total number of samples) - (Number of samples with no nonconforming chip in them)

Number of samples with no nonconforming chip in them = ³⁰C₅ = 142506 samples

Total number of samples = 658008

The number of samples of 5 that contain at least one nonconforming chip = 658008 - 142506 = 515502 samples

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Answer:

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y=2.5

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