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3 years ago

QUICKK Solve for x. You must write your answer in fully simplified form.

Mathematics

2 answers:

Ierofanga [76]3 years ago

6 0

Answer:

-5/2

Step-by-step explanation:

We start with 4x = -10 and want to solve this for x.

We divide both sides by 4 (which isolates x), obtaining:

x = -10/4

and then we reduce this to x = -5/2.

aalyn [17]3 years ago

3 0

To solve divide both sides by 4 to cancel out the 4 on the x side to get x alone. Then just do -10/4. That gives you 2.5 so (X=2.5). Hope I helped and have a great day and night

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The graph of a linear equation with two variables, x and y, is a line. There are an infinite number of solutions for a line

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The function f(x)=3(2.5)^ is shown on the graph. Fill in the blank. As x increases without bound, the graph of f(x) ____________

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The answer is B increases without bound

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3 years ago

What is the perimeter of the trapezoid with vertices Q(8, 8), R(14, 16), S(20, 16), and T(22, 8)? Round to the nearest hundredth

uysha [10]

Answer:

The perimeter of the trapezoid is $38.25\ units$

Step-by-step explanation:

we know that

The perimeter of the trapezoid is the sum of its four side lengths

In this problem

$P=QR+RS+ST+QT$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$Q(8, 8), R(14, 16), S(20, 16),T(22, 8)$

step 1

Find the distance QR

$Q(8, 8), R(14, 16)$

substitute the values in the formula

$d=\sqrt{(16-8)^{2}+(14-8)^{2}}$

$d=\sqrt{(8)^{2}+(6)^{2}}$

$d=\sqrt{100}$

$QR=10\ units$

step 2

Find the distance RS

$R(14, 16), S(20, 16)$

substitute the values in the formula

$d=\sqrt{(16-16)^{2}+(20-14)^{2}}$

$d=\sqrt{(0)^{2}+(6)^{2}}$

$d=\sqrt{36}$

$RS=6\ units$

step 3

Find the distance ST

$S(20, 16),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-16)^{2}+(22-20)^{2}}$

$d=\sqrt{(-8)^{2}+(2)^{2}}$

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$ST=8.25\ units$

step 4

Find the distance QT

$Q(8, 8),T(22, 8)$

substitute the values in the formula

$d=\sqrt{(8-8)^{2}+(22-8)^{2}}$

$d=\sqrt{(0)^{2}+(14)^{2}}$

$d=\sqrt{196}$

$QT=14\ units$

step 5

Find the perimeter

$P=10+6+8.25+14=38.25\ units$

6 0

3 years ago

Read 2 more answers

Sorry for the bad quality.

ser-zykov [4K]

Answer:

B and C

Step-by-step explanation:

8 0

3 years ago

Suppose that the perimeter a rectangle is 54 feet, and the length is 13 feet more than the width. Find the width ractangle, in f

Vesnalui [34]

Answer:7feet

Step-by-step explanation:

perimeter(p)=54ft

Width(w) +13=Length(L)

Perimeter=2xLength+2xwidth

P=2xL+2xw

L=w+13

54=2(w+13)+2w

54=2w+26+2w

Collect like terms

54-26=2w+2w

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Divide both sides by 4

28/4=4w/4

7=w

Width =7feet

8 0

3 years ago