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Anarel [89]
2 years ago
7

Deena has a tool box in the shape of a right rectangular prism. The volume of the tool box is 0.375 cubic feet. The height of th

e tool box is 0.5 feet, and the length is 1.5 feet. What is the width of Deena's tool box? Enter your answer as a decimal in the box.
Mathematics
2 answers:
zaharov [31]2 years ago
7 0

Answer:

0.5 ft

Step-by-step explanation:

The applicable volume formula is ...

V = length · width · height

Filling in the given numbers, we can solve for the width.

0.375 ft^3 = (1.5 ft) · width · (0.5 ft)

Dividing by the coefficient of width, we have ...

0.375 ft^3/(0.75 ft^2) = width = 0.5 ft

The width of Deena's tool box is 0.5 ft.

Blababa [14]2 years ago
6 0

Answer:

0.5

Step-by-step explanation:

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69.5 is What precent of 85?
kenny6666 [7]
69.5 percent of 85 is 59.075 
3 0
3 years ago
Read 2 more answers
A marketing consultant observed 40 consecutive shoppers to estimate the average money spent by shoppers in a supermarket store.
KonstantinChe [14]

Answer:

0.998 is the probability that the average money spent by  a sample of 40 shoppers is within $10 of the actual population mean.

Step-by-step explanation:

We are given the following information in the question:

Standard Deviation, σ = $21.51

We are given that the distribution of average money spend is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

We have to find:

P( average money spent is within $10 of the actual population mean.)

= P( z \leq \displaystyle\frac{10\times \sqrt{40}}{21.51}}) = P(z \leq 2.94)

Calculation the value from standard normal z table, we have,  

P(z \leq 2.94) = 0.998

6 0
3 years ago
This figure is made up of a rectangle and parallelogram.
ivann1987 [24]

The area of the figure is 40 units. (rounded off from 39.998 units)

Step-by-step explanation:

1. Area of the figure = Area of Rectangle + Area of Parallelogram.

2. Naming points:

Let the rectangle consist of points A(-6,-1), B(-5,-5), C(3,-3) and D(2,1).

Let the parallelogram consist of points C(3,-3), D(2,1), E(2,7) and F(3,3).

3. Each coordinate has a point on the x-axis and a point on the y-axis. We shall refer to these points as x', x'' ,x''' and so on corresponding to the x-axis values of A, B, C and so on in that order till F. For the y-axis points, we will name them in the series of y', y'', y''' and so on.

In simple words, in A(-6,1), x' = -6; y' = -1

4. Formula for finding area:

Area of a rectangle = length (l) × width (w)

Area of a parallelogram = base (b) x height (h)

5. Finding area of the rectangle:

l = AD = \sqrt{[x'''' - x']^{2} - [y'''' - y']^{2}}

, i.e. AD = \sqrt{[2 - (-6)]^{2} - [1 - (-1)]^{2}}

, i.e. AD = √68 = 8.246 (rounded to 3 decimals) = l

Now, w = AB = \sqrt{[x'' - x']^{2} - [y'' - y']^{2}}

, i.e. AB = \sqrt{[(-5) - (-6)]^{2} - [(-5) - (-1)]^{2}}

, i.e. AB = √17 = 4.123 (rounded to 3 decimals) = w

Area of rectangle = l x w = 8.246 x 4.123 = 33.998 units.

6. Finding area of the parallelogram:

b = DE = 6 units (we can observe this from the graph, i.e. points from 1 to 7 on the y axis)

h = Height is the line drawn perpendicular to the base from point F, which as we can see is 1 unit long.

Hence, Area of parallelogram = b x h = 6 x 1 = 6 units.

7. Now, adding both, we can arrive at the final answer.

Area of the figure = Area of rectangle + Area of parallelogram,

i.e. 33.998 units + 6 units = 39.998 units. (can be rounded off to 40 units)

4 0
2 years ago
Which expression is equivalent to (3x2-6) – (5x2 - 7x+5)-(9x + 3)?
andrezito [222]

Answer:

It equals -2

Step-by-step explanation:

4 0
2 years ago
F(x)=2x^2-3x+7 evaluate f(-2)
Vilka [71]

Answer:

Step-by-step explanation:

Find two linear functions p(x) and q(x) such that (p (f(q(x)))) (x) = x^2 for any x is a member of R?

Let  p(x)=kpx+dp  and  q(x)=kqx+dq  than

f(q(x))=−2(kqx+dq)2+3(kqx+dq)−7=−2(kqx)2−4kqx−2d2q+3kqx+3dq−7=−2(kqx)2−kqx−2d2q+3dq−7  

p(f(q(x))=−2kp(kqx)2−kpkqx−2kpd2p+3kpdq−7  

(p(f(q(x)))(x)=−2kpk2qx3−kpkqx2−x(2kpd2p−3kpdq+7)  

So you want:

−2kpk2q=0  

and

kpkq=−1  

and

2kpd2p−3kpdq+7=0  

Now I amfraid this doesn’t work as  −2kpk2q=0  that either  kp  or  kq  is zero but than their product can’t be anything but  0  not  −1 .

Answer: there are no such linear functions.

6 0
2 years ago
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