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muminat
3 years ago
8

Describe how to write an ion

Chemistry
2 answers:
Papessa [141]3 years ago
6 0

Answer:

When writing an ion, state symbols of the substances must be clearly indicated.I HOPE IT HELPS I MADE AN EXAMPLE TOO:)

Explanation:

<u>Example: </u>

<u> Write the ionic equation for the word equation </u>

Sodium chloride(aq) + silver nitrate(aq) → silver chloride(s) + sodium nitrate(aq)

<u> Solution: </u>

<u> Step 1: </u>Write the equation and balance it if necessary

NaCl(aq) + AgNO3(aq) → AgCl(s) + NaNO3(aq)

<u>Step 2: </u>Split the ions. (Only compounds that are aqueous are split into ions.)

Na+(aq) + Cl-(aq) + Ag+(aq) + NO3-(aq) → AgCl(s) + Na+(aq) + NO3-

<u>Step 3: </u>Cancel out spectator ions. (Spectator ions are ions that remain the same in their original states before and after a chemical reaction.)

<u> Ionic Equation </u>

<u>Step 4: </u>Write a balanced ionic equation

Ag+(aq) + Cl-(aq) → AgCl(s)

IrinaVladis [17]3 years ago
5 0

Answer:

Cations (positively-charged): With a superscript + (e.g. \mbox{Na^{+}})

Anions (negative-charged): With a superscript - (e.g. \mbox{Cl^{-}})

Explanation:

An <em>ion</em> is an atom that carries some sort of negative or positive charge due to losing or gaining electrons in bonding with another atom. A <em>cation</em>, a positively-charged ion, loses an electron in the bonding process, and is written with a small plus sign superscript, while an <em>anion</em>, a negatively-charged ion, is written with a small minus sign. For example, a sodium cation in a sodium chloride molecule would be written like \mbox{Na^{+}}, and the corresponding chloride anion would be written like \mbox{Cl^{-}})

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3 years ago
A 35.0-ml sample of 0.20 m lioh is titrated with 0.25 m hcl. What is the ph of the solution after 23.0 ml of hcl have been added
kiruha [24]
<h3><u>Answer;</u></h3>

pH = 12.33

<h3><u>Explanation;</u></h3>

The equation of reaction is :

LiOH(aq) + HCl(aq) --> LiCl(aq) + H2O(l)

Reactants left after the titrant is added;

Total Moles LiOH;

= 0.035L LiOH × (0.2moles/L)

= 0.007moles of LiOH

Moles of HCl;

= 0.023L HCl × (0.25moles/L)

= 0.00575moles HCl is the limiting reagent

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= 0.0575 moles HCl *(1mole LiOH/1moles HCl)

=0.00575 moles LiOH (reacted)

Moles of LiOH left;

= 0.007moles total - 0.00575moles that react

= .00125 moles of LiOH (left)

LiOH is a strong base, which means that it ionizes completely.  

0.00125moles LiOH *(moles/0.058L) = 0.02155M of LiOH

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[LiOH] = [OH-] = 0.02155 M

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pH = 12.33

7 0
3 years ago
A client has experienced excessive losses of bicarbonate and has subsequently developed an acid–base imbalance. How will this lo
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The kidneys will excrete increased quantities of acid.

Explanation:

The kidneys will excrete excess H+ ions in the blood (remember H+ ions are responsible for acidity) until the acid-base balance is restored in the blood. Bicarbonates, on the other hand, will be aggressively  reabsorbed by the renal tubules as the excess H+ are being excreted.

The acid base balance is mainly determined by the quantities of H⁺ and HCO₃⁻ ions in teh blood. These ions come from the dissociation of carbonic acid formed when carbon dioxide from tissues is dissolved in blood plasma.

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<span>Fe(NO3)2
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Explanation:

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