Question

A gas has a solubility of 1.46 g L at 8.00 atm of pressure. What is the pressure of a sample of the same gas that

Answer 1

Answer:

$14.8\ \text{atm}$

Explanation:

$C_1$ = Initial concentration = 1.46 g/L

$C_2$ = Final concentration = 2.7 g/L

$P_1$ = Initial pressure = 8 atm

$P_2$ = Final pressure

From Henry's law we have the relation

$\dfrac{C_2}{C_1}=\dfrac{P_2}{P_1}\\\Rightarrow P_2=\dfrac{C_2}{C_1}P_1\\\Rightarrow P_2=\dfrac{2.7}{1.46}\times 8\\\Rightarrow P_2=14.8\ \text{atm}$

The pressure of a sample of the same gas at the required concentration is $14.8\ \text{atm}$.