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monitta
3 years ago
5

in a sequence of positive integers, the ratio of each term to the term immedialy following it is 1 to 4. What isnthe ratio of th

e 2nd term and 5th term
SAT
1 answer:
Kazeer [188]3 years ago
6 0

A few years ago an apparatus was devised for enlarging drawings, &c., from a facsimile ... in the ratio of two In“ gers; then we are told that the corresponding term in the ... And how can we be sure that such integers could not be found in every case! ... will be a satellite of the other; but let us take as an example the ratio 1 to 2.

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<h3>What is olfactory system?</h3>

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ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2 . If the area of ΔMNO is 10 square units, what's the area of
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Read 2 more answers
Factor the expression into an equivalent form 12y^2-75.
elena-14-01-66 [18.8K]

Hello oddworld7836!

\huge \boxed{\mathbb{QUESTION} \downarrow}

Factor the expression into an equivalent form 12y² - 75.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

12 y ^ { 2 } - 75

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

12 y ^ { 2 } - 75 \\  = 3\left(4y^{2}-25\right)

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

  • a² = 4, a = 2 (√a² = ✓4 = 2)
  • b² = 25, b = 5 (√b² = ✓25 = 5)

So, the (4y² + 25) becomes...

(4 {y}^{2}  - 25) \\  = \left(2y-5\right)\left(2y+5\right)

Now, bring the 3 (common factor) & rewrite the complete expression.

12 y ^ { 2 } - 75 \\  =  \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

__________________

Hope it'll help you!

ℓu¢αzz ッ

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