Question

Pivot the system about the element in row 2, column 1. (Enter the augmented matrix with all cells in their original position.)

Answer 1

Answer:

Step-by-step explanation:

pivoting means producing a unit column in  matrices.

The aim is to make the elements above and below the pivot element o.

so we have;

$\left[\begin{array}{cccc}1&2&4&3\\2&8&6&4\\-1&4&2&3\end{array}\right]$

we will make the pivot element a unit element that is 1.

$\frac{1}{2}R_{2}$  → $\left[\begin{array}{cccc}1&2&4&3\\1&4&3&2\\-1&4&2&3\end{array}\right]$

next we perform the operation $R_{1}$ - $R_{2}$ then we have

$\left[\begin{array}{cccc}0&-2&1&1\\1&4&3&2\\-1&4&2&3\end{array}\right]$

next we also perform the operation $R_{3} + R_{2}$ thus we have

$\left[\begin{array}{cccc}0&-2&1&1\\1&4&3&2\\0&8&5&5\end{array}\right]$