I order to solve this you have to find out how how much root beer there is to the total amount of candy. 12/27. Then you find out what the percentage of root beer there is by dividing 12 by 27. It’ll give you a decimal point. Percentage has a maximum of 100%. And you’ll find out what percent based on this decimal. Factor it out of 1. The percentage you get is .44. By factoring out of 1 you can find out that the percentage is 44%. So the probability of finding a root beer out of all the candy is roughly 44%
The class width for this Frequency Distribution Table is 5.
<h3>What is the class width?</h3>
The class width is the difference between the upper boundary and the lower boundary of the class.
The class width = upper boundary - lower boundary
5 - 0 = 5
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To work out the Circumference of a circle, we must o the calculation
πd
π x d
If we fill in the information we know
π x 10.4
3.14 x 10.4 (to 2 d.p.)
↓
32.656 (units)
Here are the unit rates involved:
$7.68 / 1 case = $7.68 per case
$7.68 / 24 cans = $0.32 per can
1 case / $7.68 = 0.13 case per $
24 cans / $7.68 = 3.125 cans per $
And of course ...
24 cans / 1 case = 24 cans per case
1 case / 24 cans = 0.041666... case per can