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Romashka [77]
3 years ago
9

1. Name three alkanes and state a use for each.

Chemistry
2 answers:
Triss [41]3 years ago
7 0

1. The simplest alkane is the gas methane, whose molecular formula is CH4. Methane exists as a tetrahedral shape, but it is often represented by a flattened structure as are most organic compounds.

Two four-carbon alkanes are known, and they have measurably different chemical and physical properties.  Their structures are H3CCH2CH2CH3 and H3CCH(CH3)2.  Therefore they were named normal butane, often abbreviated as n-butane, and isobutane.  The straight-chain form is considered the "normal" form.  Alternatively, they could be named using the systematic IUPAC method as 1-methylpropane and 2-methylpropane, or even as butane and 2-methylpropane.  The IUPAC method names the longest straight carbon chain in the usual way and then numbers the carbons; the location of a substituent group is given by the number of its carbon.  The IUPAC method is always used for more complicated molecules, but many of the simpler ones still use non-systematic names, called trivial names, because these are less cumbersome to use.

2 . Unsaturated hydrocarbons are hydrocarbons that have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may added to the hydrocarbon to make it saturated: consisting all single bonds.

Dont know 3. Sorry!

podryga [215]3 years ago
3 0
Idk about 1, but for 2a: saturated means that all carbons have the maximum amount of hydrogens attached to them, and unsaturated means that they don’t. Only alkanes are saturated because they have all single bonds, so they have the max amt of hydrogens bonded to the carbons. 2b: saturated: butane, octane, methane. Unsaturated: ethene, butene.
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4 0
3 years ago
The pKa of chloroacetic acid is 2.9. If an organic chemist has a 0.10 M aqueous solution of chloroacetic acid at pH 2.4, what pe
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The answer is given below.

Explanation:

We will consider the acid as HA and will set up an ICE table with the equilibrium dissociation of α.

AT pH 2.4 the initial H+ concentration will be 3.98^10-3 M

                      HA →              H+         +      A-

Initial concentration:  0.1    →  3.98 ^10-3       +      0

equilibrium concentration:  0.1(1-α) →   3.98 * 10-3 + 0.1α              0.1α

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