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Romashka [77]
3 years ago
9

1. Name three alkanes and state a use for each.

Chemistry
2 answers:
Triss [41]3 years ago
7 0

1. The simplest alkane is the gas methane, whose molecular formula is CH4. Methane exists as a tetrahedral shape, but it is often represented by a flattened structure as are most organic compounds.

Two four-carbon alkanes are known, and they have measurably different chemical and physical properties.  Their structures are H3CCH2CH2CH3 and H3CCH(CH3)2.  Therefore they were named normal butane, often abbreviated as n-butane, and isobutane.  The straight-chain form is considered the "normal" form.  Alternatively, they could be named using the systematic IUPAC method as 1-methylpropane and 2-methylpropane, or even as butane and 2-methylpropane.  The IUPAC method names the longest straight carbon chain in the usual way and then numbers the carbons; the location of a substituent group is given by the number of its carbon.  The IUPAC method is always used for more complicated molecules, but many of the simpler ones still use non-systematic names, called trivial names, because these are less cumbersome to use.

2 . Unsaturated hydrocarbons are hydrocarbons that have double or triple covalent bonds between adjacent carbon atoms. The term "unsaturated" means more hydrogen atoms may added to the hydrocarbon to make it saturated: consisting all single bonds.

Dont know 3. Sorry!

podryga [215]3 years ago
3 0
Idk about 1, but for 2a: saturated means that all carbons have the maximum amount of hydrogens attached to them, and unsaturated means that they don’t. Only alkanes are saturated because they have all single bonds, so they have the max amt of hydrogens bonded to the carbons. 2b: saturated: butane, octane, methane. Unsaturated: ethene, butene.
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A chemist dissolves 240mg of pure barium hydroxide in enough water to make up of solution. Calculate the pH of the solution. (Th
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pH = 12.22

Explanation:

<em>... To make up 170mL of solution... The temperature is 25°C...</em>

<em />

The dissolution of Barium Hydroxide, Ba(OH)₂ occurs as follows:

Ba(OH)₂ ⇄ Ba²⁺(aq) + 2OH⁻(aq)

<em>Where 1 mole of barium hydroxide produce 2 moles of hydroxide ion.</em>

<em />

To solve this question we need to convert mass of the hydroxide to moles with its molar mass. Twice these moles are moles of hydroxide ion (Based on the chemical equation). With moles of OH⁻ and the volume we can find [OH⁻] and [H⁺] using Kw. As pH = -log[H⁺], we can solve this problem:

<em>Moles Ba(OH)₂ molar mass: 171.34g/mol</em>

0.240g * (1mol / 171.34g) = 1.4x10⁻³ moles * 2 =

2.80x10⁻³ moles of OH⁻

<em>Molarity [OH⁻] and [H⁺]</em>

2.80x10⁻³ moles of OH⁻ / 0.170L = 0.01648M

As Kw at 25°C is 1x10⁻¹⁴:

Kw = 1x10⁻¹⁴ = [OH⁻] [H⁺]

[H⁺] = Kw / [OH⁻] = 1x10⁻¹⁴/0.01648M = 6.068x10⁻¹³M

<em>pH:</em>

pH = -log [H⁺]

pH = -log [6.068x10⁻¹³M]

<h3>pH = 12.22</h3>
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