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FromTheMoon [43]
2 years ago
14

What is the measure of the missing angle in a triangle that contains angle measures of 37° and 59°?

Mathematics
1 answer:
Vera_Pavlovna [14]2 years ago
4 0

Answer:84 degrees

Step-by-step explanation:

so if a triangle is 180 degrees in total you need to find how much you need to equal that so you add 59+37=96 degrees so then you will subtract 180-96=84 degrees

Your welcome!

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Jenny bought a $50 jacket. If the sales tax rate is 8%, how much tax did she pay?
OlgaM077 [116]

Answer:

54$

Step-by-step explanation:

  • To get the tax times the number to the percentage
  • 50 * 8% = 4
  • 50 + 4 = 54 $
8 0
1 year ago
Ahhhh someone please help, 40 points!
valina [46]

Answer:

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2 years ago
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Subtract 8-4 1/2. A. 3 B. 4 C. 4 1/2 D. 3 1/2
Leokris [45]
1.
An expression of the form a \frac{b}{c} is called a "compound fraction"
 
Compound fractions can be written as simple fractions by multiplying c to a, and then adding the product to c as follows:

a \frac{b}{c}= \frac{c.a+b}{c}

for example, 

4\frac{1}{2} can be written as: 

4\frac{1}{2}= \frac{2.4+1}{2}=\frac{9}{2}

2.

when we subtract or add a fraction \frac{m}{n} from an integer k, 

we first write k as a fraction with denominator n. We can do this as follows:

k=k. \frac{n}{n}= \frac{kn}{n}

for example, if we want to subtract \frac{9}{2} from 8, 

we first write 8 as a fraction with denominator 2:

8=8. \frac{2}{2}= \frac{8.2}{2}= \frac{16}{2}

3.

Thus, 

8-4 \frac{1}{2}= \frac{16}{2}- \frac{9}{2}= \frac{16-9}{2}= \frac{7}{2}

4.

The simple fraction 7/2 is not an option, so we write it as a compound fraction as follows:

\frac{7}{2}= \frac{6+1}{2}= \frac{6}{2}+ \frac{1}{2}=3+ \frac{1}{2}=3\frac{1}{2}

(So write 7 as the sum of the largest multiple of 2, smaller than 7 + what is left. In our case these numbers are 6 and 1, then proceed as shown)

5. Answer: D
3 0
3 years ago
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4. What are the zeros of the polynomial function y= 2x2-3x+1?
weeeeeb [17]

Answer:

A

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Given

y = 2x² - 3x + 1

To find the zeros let y = 0, that is

2x² - 3x + 1 = 0

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product = 2 × 1 = 2 and sum = - 3

The factors are - 2 and - 1

Use these factors to split the x- term

2x² - 2x - x + 1 = 0 ( factor the first/second and third/fourth terms )

2x(x - 1) - 1(x - 1) = 0 ← factor out (x - 1) from each term

(x - 1)(2x - 1) = 0

Equate each factor to zero and solve for x

2x - 1 = 0 ⇒ 2x = 1 ⇒ x = \frac{1}{2}

x - 1 = 0 ⇒ x = 1

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