All categories

3 years ago

What happens as the two air masses collide

1 answer:

7 0

If the boundary between the cold and warm air masses doesn't move, it is called a stationary front. The boundary where a cold air mass meets a cool air mass under a warm air mass is called an occluded front. At a front, the weather is usually unsettled and stormy, and precipitation is common.

You might be interested in

Balance the following unbalanced redox reaction (assume acidic solution if necessary): Cr2O72- + Cl- → Cl2 + Cr3+ Indicate the c

sergejj [24]

Answer:

14 H⁺ + Cr₂O₇²⁻ + 6Cl⁻ → 3Cl₂ + 2Cr³⁺ + 7H₂O

The coefficient that will be used for Cl₂ in this reaction is 3

Explanation:

We use the method of electron-ion to the balance.

We assume that the redox reaction is happening at acidic medium.

Cr₂O₇²⁻ + Cl⁻ → Cl₂ + Cr³⁺

Chloride is raising the oxidation state from -1 in the chloride, to 0 in the chloride dyatomic. This is the half reaction of oxidation

2Cl⁻ → Cl₂ + 2e⁻ Oxidation

In the dichromate anion, chromium acts with +6 in oxidation state, and we have 2 Cr, so the global charge of the element is +12. To change to Cr³⁺ it has release 3 electrons, but we have 2 Cr, so it finally released 6 e-. The oxidation state was decreased, so this is the reduction half reaction.

14 H⁺ + Cr₂O₇²⁻ + 6e⁻ → 2Cr³⁺ + 7H₂O Reduction

As we have 7 O in the product side, we add 7 water, to the opposite place. In order to balance the H (protons) we, add the amount of them, in the opposite side, again.

(2Cl⁻ → Cl₂ + 2e⁻) ₓ3

(14 H⁺ + Cr₂O₇²⁻ + 6e⁻ → 2Cr³⁺ + 7H₂O) ₓ1

We multiply the half reactions, in order to remove the electrons and we sum, the equations:

14 H⁺ + Cr₂O₇²⁻ + 6e⁻ + 6Cl⁻ → 3Cl₂ + 6e⁻ + 2Cr³⁺ + 7H₂O

Now, that we have the same amount of electrons, they can cancelled, so the balanced redox reaction is:

14 H⁺ + Cr₂O₇²⁻ + 6Cl⁻ → 3Cl₂ + 2Cr³⁺ + 7H₂O

4 0

3 years ago

Read 2 more answers

In chemistry lab student is determining the salinity of seawater using a conductivity meter. The student made standards of NaCl

dimaraw [331]

Answer:

a. is an excel document. i uploaded as an attachment

b. concentration = 0.327

Explanation:

in the graph i uploaded for answer a, the x variable is conductivity, while the y variable is % salinity.

the calculated regression line was calculated using excel =

y = 0.057655X - 0.00891

for answer part b,

we take x = 5.82

when we put this into the y formular

y = 0.057655(5.82) - 0.00891

y = 0.3355521 - 0.00891

y = 0.3266421

this is ≈ 0.327

in conclusion, using the standard curve, the concentration of unknown salt is 0.327. the % salinity = 0.327

6 0

3 years ago

A 37.2-g sample of lead (Pb) pellets at 20Â°C is mixed with a 62.7-g sample of lead pellets at the same temperature. What are th

Vesnalui [34]

Answer:

Mass of sample is 99.9 g, density of ample is 11.35 $g/cm^{3}$ and temperature of sample is $20^{0}\textrm{C}$

Explanation:

Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.

Mass of combined sample = (37.2+62.7) g = 99.9 g

Density is an intensive property. Therefore density of combined sample of lead will be same as with density of Pb.

Density of combined sample = 11.35 $g/cm^{3}$

Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.

temperature of combined sample = $20^{0}\textrm{C}$

8 0

3 years ago

I do not understand this question if someone could help please

zzz [600]

$\bold{\huge{\blue {\underline{ Answer}}}}$

Potassium = K3PO4 , K2O, KF, KBr, KNO2 , K2SO4 
Sodium = Na3PO4 , Na2O, NaF, NaBr, NaNO3 , Na2SO4
Magnesium = Mg3(PO4)2 , MgO, MgF2 , MgBr2 , Mg3NO2 , MgSO4 
Aluminium = AlPO4 , Al2O3 , AlF3 , AlBr3 , AlNO2 , Al2(SO4)3
Iron(|||) = FePO4 ,  Fe2O3 , FeF3 , FeBr3 , FeNO2 , Fe2(SO4)3 
Copper(||) = Cu3(PO4)2 , CuO, CuF2 , CuBr2 , Cu3NO2 , CuSO4
Barium = Ba3(PO4)2 , BaO, BaF2 , BaBr2 , Ba3NO2 , BaSO4 .

4 0

2 years ago

4. Which of the following elements does NOT belong to

marusya05 [52]

========== tellurium Te

7 0

3 years ago