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Luda [366]
3 years ago
6

Fe + CuCl2 → FeCl2 + Cu

Chemistry
1 answer:
inna [77]3 years ago
5 0

Answer:

the type is single replacement

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Solve for a, b, c, AND d<br> d<br> C<br> 84°<br> 930<br> 970<br> b
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Answer:

a = 87

b = 83

c = 96

d = 86

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Compare and contrast nitrogen and phosphorus cycles
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The phosphorous cycle does not include an atmospheric component because phosphorous does not cycle through the atmosphere. In comparison, important processes of the carbon and nitrogen cycle occur in the atmosphere

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Which of the following most likely requires intermolecular forces?
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Answer: The intermolecular forces increase with increasing polarization of bonds. Boiling point increases with molecular weight, and with surface area. The three major types of intermolecular interactions are dipole–dipole interactions, London dispersion forces (these two are often referred to collectively as van der Waals forces), and hydrogen bonds. Intermolecular forces are much weaker than the intramolecular forces of attraction but are important because they determine the physical properties of molecules like their boiling point, melting point, density, and enthalpies of fusion and vaporization.In order from strongest to weakest, the intermolecular forces given in the answer choices are: ion-dipole, hydrogen bonding, dipole-dipole, and Van der Waals forces. Ionic bonding is stronger than any of the given intermolecular forces, but is itself NOT an intermolecular force.

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A gas balloon has a volume of 106.0 liters when the temperature is 25.0 °C and the pressure is 740.0 mm Hg. What will its volume
ipn [44]

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Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 740.0 mmHg  = 98.4 kPa

Conversion used : (1 mmHg = 0.133 kPa)

P_2 = final pressure of gas = 99.3 kPa

V_1 = initial volume of gas = 106.0 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 25.0^oC=273+25.0=298K

T_2 = final temperature of gas = 20.0^oC=273+20.0=293K

Now put all the given values in the above equation, we get:

\frac{98.4kPa\times 106.0L}{298K}=\frac{99.3kPa\times V_2}{293K}

V_2=103.3L

Therefore, the final volume of gas will be, 103.3 L

8 0
4 years ago
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