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QveST [7]
4 years ago
10

Rank the compounds in each set in order of increasing acid strength.

Chemistry
1 answer:
Viktor [21]4 years ago
5 0

Answer:

See explanation

Explanation:

For this question, we have to remember the effect of an atom with high <u>electronegativity</u> as "Br". If the "Br" atom is closer to the carboxylic acid group (COOH) we will have an <u>inductive effect</u>. Due to the electronegativity of Br, the electrons of the C-H bond would be to the Br, then this bond would be <u>weaker</u> and the compound will be more acid (because is easier to produce the hydronium ion H^+).

With this in mind, for A in the last compound, we have <u>2 Br atoms</u> near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have <u>more acidity</u>. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the <u>position</u> of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a <u>higher inductive effect</u> and more <u>acidity</u>.

See figure 1

I hope it helps!

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What is the volume of a substance that has a density of 13.6 g/cm and a mass of 3.0 g?
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Answer:

\boxed {\boxed {\sf v \approx  0.22 \ cm^3}}

Explanation:

We are asked to find the volume of a substance.

We are given the density and the mass. The density of a substance is its mass per unit volume. The formula for calculating density is:

\rho= \frac{m}{v}

We know the density of the substance is 13.6 grams per cubic centimeter and the mass is 3.0 grams.

  • ρ= 13.6 g/cm³
  • m= 3.0 g

Substitute these values into the formula.

13.6 \ g/cm^3= \frac{3.0 \ g }{v}

We are solving for the volume, so we must isolate the variable v. First, cross multiply. Multiply the first numerator by the second denominator, then multiply the first denominator by the second numerator.

\frac{13.6 \ g/cm^3}{1}= \frac{3.0 \ g }{v}

13.6 \ g/cm^3 *v =3.0 \ g *1

Multiply on the right side of the equation.

13.6 \ g/cm^3 *v =3.0 \ g

The variable is being multiplied by 13.6 grams per cubic centimeters. The inverse operation of multiplication is division, so we divide both sides of the equation by 13.6 g/cm².

\frac {13.6 \ g/cm^3 *v}{13.6 \ g/cm^3} =\frac{3.0 \ g }{13.6 \ g/cm^3}

v =\frac{3.0 \ g }{13.6 \ g/cm^3}

The units of grams cancel.

v =\frac{3.0  }{13.6 \ cm^3}

v= 0.2205882353 \ cm^3

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v \approx 0.22 \ cm^3

The volume of the substance is approximately <u>0.22 cubic centimeters.</u>

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