Let's get the data out of the problem:

Nv = 18

Ov = 12

Now, we can apply in this equation that relates the new and the old values:

i = Nv / Ov

i = 18 / 12

i = 1.5

Now, we just consider what has passed from 1, and this is 0.5, converting to percentage it is:

p = 0.5 . 100

p = 50%

The increase was 50%.

Hope it helps.

4 0

3 years ago

What is the area of this figure?

vovangra [49]

Witch one are u takin about bc if it's the square the answer is 16 if ur taking about the rain gel the answer is 24

7 0

3 years ago

6x-27=-3x<br><br> solve for x:D

son4ous [18]

Answer:

6×-27=-3×

+3×

9/9×=27/9

×=3

7 0

3 years ago

In the city of Carmen, there is a drawbridge that is opened twice per hour over the summer. The graph below shows the number of

n200080 [17]

Answer:

1) Between 0 and 1 minute the rate of change is 25 ft./min

2) Between 1 and 2 minute the rate of change is 0 ft./min

3) Between 2 and 4 minute the rate of change is -12.5 ft./min

Step-by-step explanation:

1) Between 0, and 1 feet, we have;

The rate of change = (Final height - Initial height)/(Final time - Initial time)

The rate of change = (40 - 15)/(1 - 0) = 25 ft/min

Between 0 and 1 minute the rate of change = 25 ft./min

2) Between 1, and 2 feet, we have;

The rate of change = (40 - 40)/(2 - 1) = 0 ft/min

Between 1 and 2 minute the rate of change = 0 ft./min

3) Between 2, and 4 feet, we have;

The rate of change = (15 - 40)/(4 - 2) = -12.5 ft/min

Between 2 and 4 minute the rate of change = -12.5 ft./min

7 0

3 years ago