Absolute vale of -5-i?
1 answer:
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Answer: y = x - 3
Step-by-step explanation:
Slope-intercept form is in the form of y=<em>m</em>x + <em>b</em> where m is the slope and b is the y-intercept.
We are given the slope, so we will plug this in.
y = <em>m</em>x + <em>b</em>
y = ()x + <em>b</em>
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Now, we will solve for the y-intercept by plugging in the point they give us.
y = ()x + <em>b</em>
(-2) = ()(5) + <em>b</em>
-2 = 1.25 + <em>b</em>
-3 = <em>b</em>
<em />
Lastly, we will plug this variable into the equation we wrote above for our final answer.
y = x - 3
<em>Read more about writing a </em><em>slope-intercept form</em><em> equation for this problem here:</em>
<em>brainly.com/question/13874293</em>
1)
∠BAC = ∠NAC - ∠NAB = 144 - 68 = 76⁰
AB = 370 m
AC = 510 m
To find BC we can use cosine law.
a² = b² + c² -2bc*cos A
|BC|² = |AC|²+|AB|² - 2|AC|*|AB|*cos(∠BAC)
|BC|² = 510²+370² - 2*510*370*cos(∠76⁰) =
|BC| ≈ 553 m
2)
To find ∠ACB, we are going to use law of sine.
sin(∠BAC)/|BC| = sin(∠ACB)/|AB|
sin(76⁰)/553 m = sin(∠ACB)/370 m
sin(∠ACB)=(370*sin(76⁰))/553 =0.6492
∠ACB = 40.48⁰≈ 40⁰
3)
∠BAC = 76⁰
∠ACB = 40⁰
∠CBA = 180-(76+40) = 64⁰
Bearing C from B =360⁰- 64⁰-(180-68) = 184⁰
4)
Shortest distance from A to BC is height (h) from A to BC.
We know that area of the triangle
A= (1/2)|AB|*|AC|* sin(∠BAC) =(1/2)*370*510*sin(76⁰).
Also, area the same triangle
A= (1/2)|BC|*h = (1/2)*553*h.
So, we can write
(1/2)*370*510*sin(76⁰) =(1/2)*553*h
370*510*sin(76⁰) =553*h
h= 370*510*sin(76⁰) / 553= 331 m
h=331 m
Answer:
<h2>4/5</h2>Step-by-step explanation:
Look at the picture.
We need a hypotenuse length.
Use Pythagorean theorem:
We have
Substitute:
For the sine we have:
Substitute:
